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4 years ago

Find the missing value 3/8 = _____ to 72

Mathematics

1 answer:

Morgarella [4.7K]4 years ago

3 0

Answer:

Step-by-step explanation:

First, you need to find the factor that coverts 8 to 72. I look as these problems as 3 to x and 8 to 72. To do this, divide 72 by 8, and that's what you'd multiply 3 with.

72/8 = 9

9 x 3 = 27

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Sally's soccer team played 25

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The team lost 32% of the games.

The team won 17/25 games. To find the number of games they lost, we would have to subtract 17 from 25. 25 - 17 = 8. This means the team lost 8/25 games. There are two ways I can think of. You can simply multiply 8/25 by 4/4 because 25 times 4 would equal 100. This would give you the percentage of 32. Another way is to write it like this: 8/25 = x/100. You would cross cancel to get 800 = 25(x) and divide both by 25. This would also give the answer of 32.

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Among 43,592 in-hospital patients who had cardiac arrest during the day, 23,549 survived. Among 27,963 patients at night, 7,804

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Using the z-distribution, it is found that since the p-value of the test is less than 0.01, there is enough evidence to conclude that survival rates are different for day and night.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the proportions are the same, that is, the subtraction of them is 0, hence:

$H_0: p_D - p_N = 0$

At the alternative hypothesis, it is tested if the proportions are different, that is:

$H_1: p_D - p_N \neq 0$

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

$p_D = \frac{23549}{43592} = 0.5402, s_D = \sqrt{\frac{0.5402(0.4598)}{43592}} = 0.0024$

$p_N = \frac{7804}{27963} = 0.2791, s_N = \sqrt{\frac{0.2791(0.6209)}{27963}} = 0.0025$

Hence, for the distribution of differences, they are given by:

$\overline{p} = p_D - p_N = 0.5402 - 0.2791 = 0.2611$

$s = \sqrt{s_D^2 + s_N^2} = \sqrt{0.0024^2 + 0.0025^2} = 0.0035$ .

<h3>What is the test statistic?</h3>

The test statistic is given by:

$z = \frac{\overline{p} - p}{s}$

In which p = 0 is the value tested at the null hypothesis.

Hence:

z = 0.2611/0.0035

z = 74.6.

<h3>What is the p-value of the test?</h3>

Using a z-distribution calculator, with z = 74.6, with a two-tailed test, as we are testing if the proportion is different of a value, the p-value is of 0.

Since the p-value of the test is less than 0.01, there is enough evidence to conclude that survival rates are different for day and night.

More can be learned about the z-distribution at brainly.com/question/13873630

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