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2 years ago

An angle is formed by two rays that share the same endpoint? True or False

Mathematics

2 answers:

Gre4nikov [31]2 years ago

8 0

Im pretty sure its true

MrRa [10]2 years ago

5 0

I swear this true its been a minute since i had geometry

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The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. the prob

Anni [7]

Given:
μ = 200 lb, the mean
σ = 25, the standard deviation

For the random variable x = 250 lb, the z-score is
z = (x-μ)/σ =(250 - 200)/25 = 2

From standard tables for the normal distribution, obtain
P(x < 250) = 0.977

Answer: 0.977

7 0

3 years ago

Great! You will purchase snacks for the painting class. You have a budget of $40. You want to buy fruit and granola bars.

goldfiish [28.3K]

Forgot the question hahaha

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3 years ago

How do i do this, I'm really really really really really really really really really really really really really really really c

loris [4]

I told this to someone else also...

The best thing ever is Photomath! Go to the app store on your phone, tablet, etc. and download Photomath. It literally does all your math for you and even shows the steps!! I use it all the time. :)

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2 years ago

Read 2 more answers

Any credit)

Mumz [18]

Answer: $4,365.10

Step-by-step explanation:

Ok, we know that:

The account starts with $2350

There is a simple interest of 3.75% (or 0.035).

Then after one year, the amount in the account will increase by 3.75%, this means that the amount will be:

$2350 + 0.035*$2350 = (1.035)*$2350.

After another year, we have the same increase (but applied to the new amount in the account):

(1.035)*$2350 + 0.035*(1.035)*$2350. = (1.035)^2*$2350

And so on.

You already can see the pattern here, the amount of money in the saving account after N years will be:

M(N) = $2350*(1.035)^N.

Now we can answer:

what is the balance of the account if it earns a simple interest of 3.75% for 18 years?

Just replace N by 18 in that equation:

M(18) = $2350*(1.035)^18 = $4,365.10

6 0

2 years ago

Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav

Furkat [3]

Answer:

There is no significant evidence that p1 is different than p2 at 0.01 significance level.

99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

$H_{0}$ : p1-p2=0

$H_{a}$ : p1-p2≠0

Test statistic can be found using the equation:

$z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of the common attribute in population1 ( $\frac{16}{30} =0.533$ )

p2 is the sample proportion of the common attribute in population2 ( $\frac{1337}{1900} =0.704$ )

p is the pool proportion of p1 and p2 ( $\frac{16+1337}{30+1900}=0.701$ )

n1 is the sample size of the people from population1 (30)

n2 is the sample size of the people from population2 (1900)

Then $z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}}$ ≈ 2.03

p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2± $z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}}$ where

z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704± $2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}}$ ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0

2 years ago