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Luden [163]
3 years ago
9

Find a numerical value of one trigonometric function of x if sin x cot x = 1/3

Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:

cosx=0.33

Step-by-step explanation:

We are given that

sinxcotx=\frac{1}{3}

We have to find the numerical value of one trigonometric function.

We know that

cotx=\frac{cosx}{sinx}

Using the formula then we get

sinx\times \frac{cosx}{sinx}=\frac{1}{3}

cox=\frac{1}{3}

cosx=0.33

Hence, the numerical value of one trigonometric function

cosx=0.33

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Please help, I need to get this done!<br>I need to get number 16, 17, and 18 done please help!!!!​
Tresset [83]

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Step-by-step explanation:

The formula to find area of a circle is: \pi r^{2}. To find radius, find the half of the diameter.

To solve number 16, first find the area of the unshaded circle using the formula: \pi 4^{2}. This is also 3.14*16. Multiply to get 50.24 m². Now find the area of the larger circle using the formula: \pi 6^{2}. This is also 3.14*36. Multiply to get 113.04 m². Now subtract 113.04 - 50.24 to get the shaded area or 62.8 m².

To solve number 17, first find the area of the square using the formula: side x side. In this case multiply: 5.25 x 5.25 to get 27.5625. Round to the nearest tenth to get 27.6 m². Now find the area of the circle using the formula: \pi 2.625^{2}. This is also 3.14*2.625. Multiply to get 8.2425. Round to the nearest tenth to get 8.2. Subtract 27.6 - 8.2 to get 19.4 m².

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Hope it helps and is correct!

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