(<span>used with a singular verb</span><span>) the systematic treatment of magnitude,relationships between figures and forms, and relations betweenquantities expressed <span>symbolically</span></span>
Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
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Im not sure if this is what you’re looking for but hope it helped!
Let the first number be = x
Then the second number = 2x
The third number = 2x - 5
Their sum = 55
This can be written in an equation as =
x + 2x + 2x - 5 = 55
= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )
= x + 2x + 2x = 60
= 5x = 60
= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )
= x = 12
The first number = x = 12
The second number = 2x = 2 × 20 = 24
The third number = 2x - 5 = 24 - 5 = 19
Therefore , the three numbers are 12 , 24 and 19 .
Answer:
43 1 ÷12
Step-by-step explanation:
The computation of the length of the original roll of papers is shown below:
36 1 ÷3 and 6 3 ÷ 4 together
Now convert the above fractions into a number
36 1 ÷ 3 = 109 ÷3
And,
6 3 ÷4 = 27 ÷ 4
Now add these two numbers i.e.
109 ÷3 + 27 ÷ 4
= 436 + 81 ÷ 12
= 517 ÷12
= 43 1 ÷12
