Perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.
As given in the question,
Coordinates of vertices K(-2,1) and M(10,6)
KM =
=
= 13units
In equilateral triangle KL = LM = KM = 13 units
Perimeter of equilateral triangle KLM = 13 +13 +13
= 39 units
Therefore, perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.
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The coordinates of point E is (-2, -1.5)
<h3>How to determine the coordinates of point E?</h3>The complete question is added as an attachment
The given parameters are
C = (1, 6)
D = (-3, -4)
The ratio 3/4 can be represented as:
m : n = 3 : 1
So, the coordinate of point E is
E = 1/(m + n) * (mx2 + nx1, my2 + ny1)
So, we have:
E = 1/(3 + 1) * (3 * -3 + 1 * 1, 3 * -4 + 1 * 6)
Evaluate
E = 1/(4) * (-8, -6)
This gives
E = (-2, -1.5)
Hence, the coordinates of point E is (-2, -1.5)
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