Answer:
x² + x - 30
Step-by-step explanation:
Given
(x - 5)(x + 6)
Each term in the second factor is multiplied by each term in the first factor, that is
x(x + 6) - 5(x + 6) ← distribute both parenthesis
x² + 6x - 5x - 30 ← collect like terms
= x² + x - 30
Answer: See below
Step-by-step explanation:
a) There is a correlation between the number of employees in the plant and the number of products produced yearly. Specifically, a positive correlation exists because, as we can see on the table, as the number of employees increases, the number of products also increases. And the rate of increase is constant.
b) Let the function be: y = mx + b
When x = 0; y = 120
So:
120 = 0 + c
c = 120
Now the slope:
Therefore, the equation that best fits the data is y = 8x + 120
c) The slope in the function represents the constant rate of change, meaning that as the number of employees increases by 1, the number of products produced monthly increases by 20. While the y-intercept of the plot, which is 120, indicates the constant number of products, that is to say, when there are no employees, there are still 120 products.
The probability of drawing a two and another 2 is 1/72
<h3>What is probability?</h3>
Probability is the likelihood or chance that an event will occur
- Since the total number in the board game is 9, hence the probability of drawing a 2 will be 1/9
- The probability of drawing the second 2 will be 1/8
- Pr(drawing a 2, then drawing another 2) = 1/9 * 1/8
Pr(drawing a 2, then drawing another 2) = 1/72
Hence the probability of drawing a two and another 2 is 1/72
learn more on probability here: brainly.com/question/24756209
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
72°
the sum of the exterior angles of a polygon = 360°
for a pentagon with 5 sides the
exterior angle = 
= 72°
