Answer:
Equation of circle in standard form with centre (0, – 10) and radius 6. 
Step-by-step explanation:
We need to write equation of circle in standard form with centre (0, – 10) and radius 6.
The equation of circle is: 
where (h,k) is centre of circle and r is radius
We are given centre (0,-10) so, h=0, k=-10 and radius r = 6
Putting values and finding equation:
So, equation of circle in standard form with centre (0, – 10) and radius 6.
Working conditions in the United States in the early 1900’s can best be described as atrocious.
Answer:
<em>The measure of the angles is 45° and 135°</em>
Step-by-step explanation:
When two lines intersect, a linear pair of angles is formed. Two angles are said to be linear if they are adjacent, so a linear pair of angles must add up to 180 degrees.
Let's call x and y the two required angles. Knowing they form a linear pair:
x+y=180
We also know one angle is 1/3 of the other angle, thus:
x=y/3
Or, equivalently:
3x=y
Substituting y into the first equation:
x+3x=180
Simplifying:
4x=180
Solving:
x=180/4=45
The other angle is:
y=3x=3\cdot 45=135
Thus the measure of the angles is 45° and 135°
Answer:
Base = 353.55 sq cm
Step-by-step explanation:
10 by 10 triangle = 45 45 90 traingle
hypotenuse = 10√2
A = 10√2 by 25
Answer:
The range here is the set {8, -10, -4, 20, 32}.
Step-by-step explanation:
Please use " ^ " to denote exponentiation. Thanks. f(x)=x^2 + 5x - 4
f(-4)=(-4)^2 + 5(-4) - 4 = 8
f(-2)=(-2)^2 + 5(-1) - 4 = -10
f(0)=0^2 + 5(0) - 4 = -4
f(3) =3^2 + 5(3) - 4 = 20
f(4)=4^2 + 5(4) - 4 = 32
In this problem we have to calculate the actual function values for the given domain (input values). The range here is the set {8, -10, -4, 20, 32}.
