Three people toss a fair coin and the odd one pays for coffee. if the coins all turn up the same, they are tossed again. find th
e probability that fewer than 4 tosses are needed.
1 answer:
Since the problem doesn’t give a definite question, here are
the possible questions and answer:
P(fewer than 4 tosses)
= P(one toss) + P(two toss) + P(3 toss)
= (3/4) + (3/4)(1/4) + (3/4)(1/4)^2
= 0.984375
Expected value
= 1 / p
= 1 / (3/4)
= 4 / 3
Variance
= (1 - p) / p^2
= (1 - (3/4)) / (3/4)^2
= (1/4) / (9/16)
= 4 / 9
Standard deviation
= sqrt(Variance)
= sqrt(4 / 9)
= 2 / 3
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Answer:
C. The three segments are segments AB, CA, and AC
Answer:
∠ 6 = 38°
Step-by-step explanation:
∠6 and 38° are vertical and congruent, thus
∠ 6 = 38°
The constant is 6. A constant is just the number on its own. Quadratics follow the form f(x) = ax^2+bx+c. The c is the constant.
First question: 0
Second question: 0.94
-6x=19+17
-6x=36 /(-6)
x=-6
