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Shkiper50 [21]
3 years ago
13

Find the area of the semicircle.

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
6 0
So we know that the area of a full circle is pi multiplied by radius squared
But for a semicircle the area is pi multiplied by radius squared divided by two
So, we do 3.14*3^2/2
Which is 14.13
vodka [1.7K]3 years ago
3 0

Answer:

14.13

Step-by-step explanation:

The formula for area of a circle is πr^2.

This is a semicircle which is half a circle, so the formula for area of a semicircle is (πr^2)/2

The diameter of the circle is 6, which means that the radius is 3. Since the radius of a circle is always half the diameter. (1/2*6=3)

This means we can plug the known values into our formula.

π(3)^2/2

Simplify.

9π/2

Now we plug 3.14 in for π.

9(3.14)/2

28.26/2

14.13

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An online clothing store had 450,082 visitors in May, 450,566 visitors in June, and 405,987 visitors in July. What is the order
blondinia [14]

Answer:

450, 566 ; 450,082 ; 405,987

Step-by-step explanation:

Number of visitors in may = 450,082

Number of visitors in June = 450,566

Number of visitors in July = 405,987

Arranging the number of visitors from greatest to least(In descending order).

450,566 > 450,082 > 405,987

450, 566 ; 450,082 ; 405,987

3 0
3 years ago
Which expression has a value of 7/12
Alenkinab [10]

Answer:

there isn't any choices but 6/12+1/12=7/12

or 4/12+3/12=7/12

hope this helps

have a good day :)

Step-by-step explanation:

5 0
2 years ago
which of the following is a statistical question ?a.how old are you ? B.do you play softball ?C.how tall are you ? D.how old are
sleet_krkn [62]
Answer is D.How old are the players on your softball team.
8 0
2 years ago
Read 2 more answers
Some people think it is unlucky if the 13th day of month falls on a Friday. show that in that there year (non-leap or leap) ther
Vlad1618 [11]
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths. Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday. Jan - Friday Feb - Monday Mar - Monday Apr - Thursday May - Saturday Jun - Tuesday Jul - Thursday Aug - Sunday Sep - Wednesday Oct - Friday Nov - Monday Dec - Wednesday Now let's count how many times for each weekday, the 13th falls there. Sunday - 1 Monday - 3 Tuesday - 1 Wednesday - 2 Thursday - 2 Friday - 2 Saturday - 1 The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc. So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get: Jan - Friday Feb - Monday Mar - Tuesday Apr - Friday May - Sunday Jun - Wednesday Jul - Friday Aug - Monday Sep - Thursday Oct - Saturday Nov - Tuesday Dec - Thursday And the weekday totals are: Sunday - 1 Monday - 2 Tuesday - 2 Wednesday - 1 Thursday - 2 Friday - 3 Saturday - 1 And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year. And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
5 0
3 years ago
Use a calculator to solve the following equation for θ on the interval [−90∘,90∘]. Sin(θ)=34
exis [7]

The value of θ from the given equation is 48.59degrees

<h3>Trigonometry identity</h3>

Given the trigonometry function

Sin(θ)=3/4

We are to find the value of theta that will make the expression true

Take the arcsin of both sides

arcsin Sin(θ)= arcsin(3/4)

θ = arcsin(3/4)

θ = 48.59

Hence the value of θ from the given equation is θ = 48.59 defense

Learn more on trig identity here:brainly.com/question/7331447

4 0
2 years ago
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