All categories

3 years ago

Can someone help me with this one ?

Mathematics

1 answer:

Shalnov [3]3 years ago

5 0

Step-by-step explanation:

Using pythagoras theorem

9^2 - 6^2 = x^2

Therefore X^2 = 81 - 36

= 45

Thus X = √45

X = 6.71

You might be interested in

How do you find the product of -9over5 times 5over 3? please help.

Inessa [10]

Here look at this for my answer...

3 0

3 years ago

When writing twenty-one-and-a-half-trillion in scientific notation, what is the exponent needed on the base ten?

Nat2105 [25]

1 trillion is 10^9.

Thus, 21 1/2 trillion is 21 1/2 times 10^9, or 2.15 times 10^10

Hope this helps. If not, ask for clarification.

5 0

3 years ago

Read 2 more answers

What is solution of 5+3(y-4)=5(y+2)-y

gulaghasi [49]

Answer:

y = -17

Step-by-step explanation:

5 + 3(y - 4) = 5(y + 2) - y Distribute

5 + 3y -12 = 5y + 10 - y Combine like terms

-7 + 3y = 4y + 10

+7 +17 Add 17 to both sides

3y = 4y + 17

-4y -4y Subtract 4y from both sides

-y = 17 Divide both sides by -1

y = -17

If this answer is correct, please make me Brainliest!

8 0

3 years ago

Read 2 more answers

State if the two triangles are similar and the rule that applies.

kobusy [5.1K]

Answer:

The SAS rule states that two triangles are similar if the ratio of their corresponding two sides is equal and also, the angle formed by the two sides is equal. Side-Side-Side (SSS) rule: Two triangles are similar if all the corresponding three sides of the given triangles are in the same proportion.

Step-by-step explanation:

3 0

2 years ago

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

stich3 [128]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Note: Same answer provided to question 14037480, answered by me.

7 0

3 years ago