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2 years ago

When two sets are equal they have ?

Mathematics

2 answers:

Nezavi [6.7K]2 years ago

6 0

Your answer should be B. Two sets are equal if they contain the same elements. Two sets are equivalent if they have the same cardinality or the same number of elements.

Hunter-Best [27]2 years ago

3 0

Answer:

Two sets are equivalent if they have the same cardinal or the same number of elements.

Step-by-step explanation:

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Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

7 0

3 years ago

Simplify. x+7/x^2+4x-21

mr_godi [17]

To silpify the expression we proceed as follows:
(x+7)/(x^2+4x-21)
Factorizing the given the denominator:
x^2+4x-21
x^2-3x+7x-21
=x(x-3)+7(x-3)
=(x-3)(x+7)
thus plugging back in our expression we have:
(x+7)/[(x-3)(x+7)]
simplifying this we obtain:
1/(x+3)

Answer: 1/(x+3)

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3 years ago

It costs twelve dollars to get in to the fair. Tickets for rides cost extra and are d dollars each

babymother [125]

Answer is d. $12+20d

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4 years ago

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Show that tanø+Cotø = Secø Cosecø

LiRa [457]

Answer:

True.

Keys:

Manipulate left/right sides

Step-by-step explanation:

$\tan \left(\theta\right)+\cot \left(\theta\right)=\sec \left(\theta\right)\csc \left(\theta\right)\\\tan \left(\theta\right)+\cot \left(\theta\right)\\=\frac{\cos ^2\left(\theta\right)+\sin ^2\left(\theta\right)}{\cos \left(\theta\right)\sin \left(\theta\right)}\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}\\\\\sec \left(\theta\right)\csc \left(\theta\right)\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}$

What was shown throughout this problem?

We showed that two different sides are capable of taking the same form.

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2 years ago

PLEASE HURRY I GOTTA GET IN TURNED IN BY 11:59 OR I FAIL

lesya692 [45]

Answer:

I think it is C. but I'm not sure

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3 years ago

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When two sets are equal they have ?​

When two sets are equal they have ?