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krok68 [10]
2 years ago
13

Solve the system of equations. 2x-6y=8 x-3y=9 Plz help I’m superrr confused

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0

Answer:

There is no solution to this system of equations. The lines do not intersect.

Step-by-step explanation:

Step 1 : See if either x or y can be eliminated.

2x-6y=8

2(x-3y=9)

2x - 6y = 8

2x - 6y = 18

There is <em>no solution</em> to this system of equations as they don't intersect. Notice how we can't cancel out the x or y without canceling the other unknown variable?

Proof : Rearranging the equations above into y = mx + b form, we get

Equation 1 : y = 1/3x - 4/3

Equation 2 : y = 1/3x - 3

A system of equations has no solution when the slopes are the same and both equations have different y intercepts.

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A point has zero dimension. True or False?
djverab [1.8K]

Answer:

True

Step-by-step explanation:

A point is zero-dimensional with respect to the covering dimension because every open cover of the space has a refinement consisting of a single open set.

7 0
3 years ago
Read 2 more answers
Worth 15 points please answer asap!!!!
ExtremeBDS [4]
So do the opposite of the answer like for example 4 +3\2 and your answer is y
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6 0
3 years ago
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
What is the answer to this question
Ganezh [65]

Answer:

9v + 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

7v + 2 + 12 + 2v

<u>Step 2: Simplify</u>

  1. Combine like terms (v):                    9v + 2 + 12
  2. Combine like terms (Z):                    9v + 14
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Please help on this problem
lubasha [3.4K]
-6 is the answer since 6*-1 is -6
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3 years ago
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