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Oliga [24]
3 years ago
12

The radius of a circle is 4 inches. What is the circle's area? p=4 in Use 3.14 for T.

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

50.27

Step-by-step explanation:

matrenka [14]3 years ago
5 0

Answer:

50.24

Step-by-step explanation:

r = 4 \\ \pi = 3.14 \\ area = \pi {r}^{2}

Input the values into the equation

3.14 \times  {4}^{2}  \\  = 3.14 \times 16  \\ = 50.24

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Order these fractions from least to greatest 6/8, 3/8, 5/8
Bess [88]

Answer:

3/8, 6/8, 5/8

Step-by-step explanation:

that is the right answer

8 0
3 years ago
What is x2-12x+36 factored
svetoff [14.1K]

How to get answer by Mimiwhatsup:

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7 0
4 years ago
The area of a rectangular glass slab is 80 square centimeters and its perimeter is 36 centimeters. If the length and width of th
netineya [11]

First, you have to find out the values of the length and width.

Let l = length and w = width.

Set up your equation for area: l * w = 80

Set up your equation for perimeter: 2l + 2w = 36

We can use substitution for this problem, so find out the value of l or w. In this case, I will use the first equation to find out the value of l.

(Divide w on both sides) l = 80 / w

Since I know that l = 80 / w, I can substitute it into the second equation.

2l + 2w = 36, and l = 80 / w

= 2 (80/w) + 2w = 36

Simplify the equation.

= 160/w + 2w = 36

Get rid of the w in the denominator by multiplying the entire equation by w.

= ( 160/w + 2w = 36 ) * w

= 160 + 2w^{2} = 36w

= 2 ( w - 8 ) ( w - 10 )

The solutions for width (w) is 8 or 10. Then, you can use both 8 and 10 as your length and width, either or is fine. Multiply by 4 for each of those values and you get 8 x 4 = 32 and 10 x 4 = 40. The new perimeter would be 2(32) + 2(40) =

a. 144 cm

Hope this helped you! Let me know if there are any confusions :)


4 0
3 years ago
Differentiate the function with respect to x<br> f(x)= x^4/ x^2- 4<br> Show work
jeyben [28]

Answer:

Step-by-step explanation:

f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}

7 0
3 years ago
Will mark brainliest plz help!
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Answer:

56

Step-by-step explanation:

hope it helps

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