The land bridge, It includes the Chukchi Sea, the Bering Sea, the Bering Strait, the Chukchi and Kamchatka Peninsulas in Russia as well as Alaska in the United States. The area includes land lying on the North American Plate and Siberian land east of the Chersky Range.
You could've just looked it up dude.
<h3>
Answer: -13</h3>
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Explanation:
g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)
g(1) = -4 means we have the point (1,-4)
Find the slope of the line through the two points (-3,2) and (1,-4)
m = (y2-y1)/(x2-x1)
m = (-4-2)/(1-(-3))
m = (-4-2)/(1+3)
m = -6/4
m = -3/2
m = -1.5
The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5
Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation: 2 = -1.5*(-3) + b
Let's solve for b
2 = -1.5*(-3)+b
2 = 4.5 + b
2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides
-2.5 = b
b = -2.5
Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5
The last step is to plug in x = 7 and compute
g(x) = -1.5*x - 2.5
g(7) = -1.5*7 - 2.5
g(7) = -10.5 - 2.5
g(7) = -13
Answer:
Side of 22 and height of 11
Step-by-step explanation:
Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:
As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank
Base area with open top 
Side area 4sh
Total surface area 
We can substitute
To find the minimum of this function, we can take the first derivative, and set it to 0
![s = \sqrt[3]{10648} = 22](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B10648%7D%20%3D%2022)
