Answer:
<em>The slope of the line is m=6. </em>
<em>The y-intercept is (0,−24). </em>
<em>The equation of the line in the slope-intercept form is y=6x−24.</em>
Step-by-step explanation:
The slope of the line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.
We have that x1=2, y1=−12, x2=5, y2=6.
Plug the given values into the formula for the slope: m=(6)−(−12)(5)−(2)=183=6.
Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).
b=−12−(6)⋅(2)=−24.
Finally, the equation of the line can be written in the form y=mx+b.
y=6x−24.
Answer:
The slope of the line is m=6.
The y-intercept is (0,−24).
The equation of the line in the slope-intercept form is y=6x−24.
Answer:
to the right of zero if postive if negative left
Answer:
<u>The slope is -3.</u>
Step-by-step explanation:
The slope is the Rise/Run between the two points. The change in y for every change in x. Take the two points and calculate the:
RISE = (-6 - 3) = -9
RUN = (8 - 5) = 3
Rise/Run, or slope, is = -9/3 or -3
I graphed a line with slope of -3 and then added 18 to force the line to intersect the two given points.
Answer:
18.852:50.272
Step-by-step explanation:
Step one:
given
The radii of two right circular cylinders are in the ratio 3 : 4
r1= 3
r2= 4
Their heights are in the ratio 1 : 2
h1= 1
h2= 2
Step two:
The expression for the curve surface area is
CSA= 2πrh
CAS1= 2πr1h1
CAS1= 2*3.142*3*1
CAS1= 18.852
CAS2= 2πr2h2
CAS2= 2*3.142*4*2
CAS1= 50.272
The ratio of their curved surface areas
=18.852:50.272