F=72
g=6
------------

Therefore:


But what is e?
E=76
G=32
g=6
And:

Which means that:

If you take this value into account, you will discover that f is...

So I would have to say that the answer is approximately (c).
i’m pretty sure the answer would be 1) linear :D
The answer is
C. 1 1/2
100% Verified
Hope This Helps!
Answer:
A is 62 b is 54 c is 62 and d is 62
And 7
Step-by-step explanation:
Since it equals to 180 you add 62 and 54 which gives u 118 then subtract it
Not sure about the second one
Given, the density of a particular brand of gasoline = 0.737 g/ml.
13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.
First we will convert 13.4 gallon to ml.
We know that 1 gallon = 3.78541 litre
And 1 litre = 1000 ml
So we can write 1 gallon =
= 3785.41 ml.
13.4 gallon =
ml = 50724.494 ml.
Let's take there is x grams of gasoline
We know that density = (mass/ volume) = 
So we can write,

To find x we will multiply both sides by 50724.494. we will get,



So we have got the required answer.
Mass of gasoline = 37383.95 grams.