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Darya [45]
2 years ago
10

Jim’s soccer team has a record of 12 wins and 8 losses. Which team below has the same rate of wins and losses?

Mathematics
1 answer:
Kipish [7]2 years ago
3 0

Answer:

D. a basketball team with 18 wins and 14 losses​

Step-by-step explanation:

Question. 12 wins - 8 loses = 4

D. 18 wins - 14 loses = 4

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The table of values represents an exponential function ​f(x). What is the average rate of change over the interval −2≤x≤2 ? Ente
solong [7]

Answer:

2.50

Step-by-step explanation:

The average rate of change over the interval −2≤x≤2 is:

(f(2) − f(-2)) / (2 − -2)

From the table, we see that f(2) = 14 and f(-2) = 4.

(14 − 4) / (2 − -2)

10 / 4

2.50

8 0
3 years ago
Solve the equation: <br> 2x + B= C<br><br> X=
Angelina_Jolie [31]
Add (-2X) to both sides:
2X + B + (-2X) = C + (-2X)
If we (rearrange) it into B + 2X + (-2X) = C + (-2X)
B + 2X - 2X = C + (-2X)
Since +2X - 2X = 0
B + 0 = C + (-2X)
B = C + (-2X)
B = C - 2X
6 0
4 years ago
Pls help
Tresset [83]

Answer:

Jimmy has a ratio of 1:20, or 1 page:20 seconds. Carlo has a ratio of 1:30, or 1 page:30 seconds. Jimmy reads at a faster pace than Carlo, as he is able to read a page in 2/3 of the time it takes Carlo.

Step-by-step explanation:

Jimmy reads a page, on average, every 20 seconds.

5 × 60 = 300

300/15 = 20

therefore, one page every 20 seconds

1:20

Carlo reads a page, on average, every 30 seconds.

6 × 60 = 360

360/12 = 30

therefore, one page every 30 seconds

1:30

7 0
1 year ago
Read 2 more answers
I have one more math question
Mademuasel [1]
I believe it’s all day pass aka bi believe it’s all day pass, AKA B
7 0
3 years ago
Calculus= Integrate 5^x dx please break down how answer is 1/6x^6+C
aleksley [76]

Answer:

\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c

Step-by-step explanation:

Note that the integral of 5^x is not \frac{1}{6}x^6 + c

The solution is as follows:

Given

5^x

Required

Integrate

Represent the given expression using integral notation

\int\limits {5^x} \, dx

This question can't be solved directly;

We'll make use of exponential rules which states;

\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c

By comparing \int\limits {5^x} \, dx with \int\limits {a^x} \, dx;

we can substitute 5 for a;

Hence, the expression \int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c becomes

\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c

-------------------------------------------------------------------------------------

However, the integral of x^5 is \frac{1}{6}x^6 + c

This is shown below:

Given that x^5

Applying power rule;

Power rule states that

\int\limits{x^n}\ dx = \frac{x^{n+1}}{n+1} + c

In this case (x^5), n = 5;

So, \int\limits{x^n}\ dx= \frac{x^{n+1}}{n+1} + c

becomes

\int\limits{x^5}\ dx = \frac{x^{5+1}}{5+1} + c

\int\limits{x^5}\ dx = \frac{x^{6}}{6} + c

\int\limits{x^5}\ dx= \frac{x^{6}}{6} + c

4 0
3 years ago
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