Answer:
0.665 moles of CO₂
Explanation:
The balance chemical equation for the combustion of Ethane is as follow:
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
Step 1: <u>Calculate moles of C₂H₆ as;</u>
Moles = Mass / M.Mass
Putting values,
Moles = 10.0 g / 30.07 g/mol
Moles = 0.3325 moles
Step 2: <u>Calculate Moles of CO₂ as;</u>
According to balance chemical equation,
2 moles of C₂H₆ produced = 4 moles of CO₂
So,
0.3325 moles of C₂H₆ will produce = X moles of CO₂
Solving for X,
X = 0.3325 mol × 4 mol ÷ 2 mol
X = 0.665 moles of CO₂
Answer:
952.2g SO3
Explanation:
Molar mass of C4H8S2 is 120.2363 g/mol
Mol in 750.0g = 750.0/120.2363 = 6.238 mol
1mol C4H8S2 produces 2 mol SO3
6.238 mol will produce 2×6.238 = 12.476 mol SO3
Molar mass SO3 = 32+3×16 = 80.0g/mol
Theoretical yield = 12.476×80.0 = 998.08g
The actual yield is 95.4%
Actual mass-produced = 95.4/100×998.08 = 952.2g SO3 produced
Hope it will help you.
I think it maybe 59.7852%
