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Tems11 [23]
3 years ago
15

What is the percent of Li in Li3N ? Please!!

Chemistry
2 answers:
lisabon 2012 [21]3 years ago
6 0
I think it maybe 59.7852%
rjkz [21]3 years ago
3 0

Answer: Li percentage in Li_3N is 59.8%.

Explanation: The question asks to calculate the mass percentage of Li in Li_3N .

The formula used for mass percentage of an element in a compound is:

mass percentage = (\frac{element mass}{compound mass})*100

Atomic mass of Li is 6.94 and atomic mass of N is 14.0.

There are three Li in the given compound. So, the mass of Li in the compound is = 3(6.94) = 20.82

Mass of compound = 20.82 + 14.0 = 34.82

Mass percentage of Li = (\frac{20.82}{34.82})*100  = 59.8%

Hence, the percentage of Li in Li_3N is 59.8%.

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A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
sergey [27]

Answer:

184.62 ml

Explanation:

Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

p_1=p_2 ...(i)

v_1 = 200 ml

T_1= 26 ^{\circ}C = 273+26 =299 K

T_2= 3 ^{\circ}C = 273+3 =276 K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

\frac{v_1}{T_1}=\frac{v_2}{T_2}  [from equation (i)]

v_2=\frac{T_2}{T_1} \times v_1

Putting all the given values, we have

v_2=\frac{276}{299} \times 200 = 184.62 \; ml

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0
3 years ago
How many milliliters of 1.50 M magnesium sulfate soulution is required to supply 2.50 mole of this salt?
arsen [322]

Answer:

1670 ml

Explanation:

molarity x Volume (Liters) = moles => Volume (Liters) = moles/Molarity

Volume needed = 2.50mol/1.50M = 1.67 Liters = 1670 ml.

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3 years ago
When a nonmetal bonds with another nonmetal, what type of bond is created?
Alexxx [7]

Answer: Ionic

Explanation:

6 0
3 years ago
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Calculate the molar mass of iron(III) sulfide. Round your answer to the nearest 0.1 and include units to receive credit.
Igoryamba

Answer:

207.89g

Explanation:

The formula of the compound is:

        Fe₂S₃  

Find the molar mass of the compound;

  Atomic mass of Fe  = 55.845g/mol

                              S  = 32.065g/mol

Now;

  Molar mass of  Fe₂S₃   = 2 (55.845) + 3 (32.065)

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