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4 years ago

Explain how you could convert 3/4 ton to ounces

1 answer:

8 0

Well knowing a ton is 2000lbs and 3/4 of that is 1500lbs, you would just need to multiply 1500 by gow many ounces are in a pound, which happens to be 16.
16 × 1500 = 24,000 ounces

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The APR of Lillian's savings account is 3.4%, and interest is compounded semiannually. If Lillian makes no additional deposits o

Evgen [1.6K]

The equation for that is

A = P * [ 1 + (r/n) ] ^(nt)

A = amount of money accumulated after n years, including interest.
P = principal amount (the initial amount you borrow or deposit)
r = annual rate of interest (as a decimal)
n = number of times the interest is compounded per year
t = number of years the amount is deposited or borrowed for.

In this question, P = 9700 , r = 0.034, n = 4 , t = 1

A = 9700 * [ 1 + (0.034 / 4) ] ^ (4 * 1)

= 9700 * ( 1 + 0.0085 )^4

= 9700 * (1.0085)^4

= 9700 * 1.03443596

= 10,032.60 rounded off

6 0

4 years ago

Read 2 more answers

Could someone pls help:(

dsp73

Answer:

4.5

Step-by-step explanation:

3^2=9

1/2*9=4.5

7 0

3 years ago

Read 2 more answers

The amount of time that people spend at Grover Hot Springs Spa is normally distributed with a mean of 63 minutes and a standard

PtichkaEL [24]

Answer:

a) $X \sim N(63,18)$

Where $\mu=63$ and $\sigma=18$

b) $P(X>90)=P(\frac{X-\mu}{\sigma}>\frac{90-\mu}{\sigma})=P(Z>\frac{90-63}{18})=P(Z>1.5)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.5)=1-P(Z$

c) $P(X$

$P(Z$

d) $P(60$

$P(-0.167$

e) IQR = 75.13-50.87=24.26

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the amount of time that people spend at Grover Hot Springs of a population, and for this case we know the distribution for X is given by:

$X \sim N(63,18)$

Where $\mu=63$ and $\sigma=18$

Part b

We are interested on this probability

$P(X>90)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>90)=P(\frac{X-\mu}{\sigma}>\frac{90-\mu}{\sigma})=P(Z>\frac{90-63}{18})=P(Z>1.5)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.5)=1-P(Z$

Part c

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table or excel:

$P(Z$

Part d

If we apply this formula to our probability we got this:

$P(60$

And we can find this probability with this difference:

$P(-0.167$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-0.167$

Part e

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.75$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

$P(X$