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aev [14]
3 years ago
8

2x-y=26 3x-2y=42 help

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~

One of these questions are always tricky, one thing you need to know, is you want to try to solve for one variable, and than substitute it in, to find the value of the other variable, and than plug that answer in to the original question to find the value of that other variable.

That probably sounds really confusing, so I'll just do the math, and guide you along the path...

<em>First, we are going to solve for y, and plug it into 3x-2y=42...</em><em />


2x - y = 26

2x = 26 + y

y = 2x - 26

----------------

3x - 2y = 42

3x - 2(2x - 26) = 42

3x - 4x - 52 = 42

-x - 52 = 42

-x = 94

x = -94

-----------------

3x - 2y = 42

3(-94) - 2y = 42

-282 - 2y = 42

-2y = 324

y = -162

~~~~~~~~~~~~~~~~~~

CHECK:

2x - y = 26   

<span />2(-94) - (-162) = 26

-188 + 162 = 26

-26 = 2<span>6<span /><span><span>          </span></span>CORRECT<span /></span><span /><span /><span />

--------------

3x - 2y = 42

3(-94) - 2(-162) = 42

-282 + 324 = 42

42 = 42            <span>CORRECT</span>

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Find the total surface area of this triangular prism.
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Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

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