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2 years ago

2x-y=26 3x-2y=42 help

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

3 0

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~

One of these questions are always tricky, one thing you need to know, is you want to try to solve for one variable, and than substitute it in, to find the value of the other variable, and than plug that answer in to the original question to find the value of that other variable.

That probably sounds really confusing, so I'll just do the math, and guide you along the path...

First, we are going to solve for y, and plug it into 3x-2y=42...

2x - y = 26

2x = 26 + y

y = 2x - 26

----------------

3x - 2y = 42

3x - 2(2x - 26) = 42

3x - 4x - 52 = 42

-x - 52 = 42

-x = 94

x = -94

-----------------

3x - 2y = 42

3(-94) - 2y = 42

-282 - 2y = 42

-2y = 324

y = -162

~~~~~~~~~~~~~~~~~~

CHECK:

2x - y = 26

2(-94) - (-162) = 26

-188 + 162 = 26

-26 = 26 CORRECT

--------------

3x - 2y = 42

3(-94) - 2(-162) = 42

-282 + 324 = 42

42 = 42 CORRECT

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Answer:

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Step-by-step explanation:

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Minimum, Median, Maximum, Q3 and Q1

See attachment for complete question

Required

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So, we have:

Minimum < < < < Maximum

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This implies that:

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2 years ago

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify given limit.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

Step 2: Find Limit

Let's start out by directly evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have evaluated the given limit.

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Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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1 year ago

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Step-by-step explanation:

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3 years ago

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velikii [3]

Answer:

"Team C scored 130 points."

Step-by-step explanation:

Let x represent how many points team B scored.

Team A: 3x + 6

Team B: x

Team C: x + 45

Total: 476 points

476 = (x) + (3x + 6) + (x + 45)

476 = x + 3x + 6 + x + 45

476 = 5x + 51

425 = 5x

x = 85

Team A:

3(85) + 6

= 261 pts

Team B:

= 85 pts

Team C:

(85) + 45

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2 years ago

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Which is the best approximation to a solution of the equation e^x = 2x + 3?

TiliK225 [7]

The correct question is
Which is the best approximation to a solution of the equation
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e^(2x) = 2e^{x) + 3-----------> e^(2x)- 2e^{x) - 3=0
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then
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3 years ago