The initial value of the linear relationship is 5.
Solution:
- The y-intercept is the point where the line crosses at y-axis.
- The initial value of the linear function is the y-intercept.
On observing the graph, the line crosses y-axis at the point (0, 5).
So, y-intercept = 5
That is initial value = 5
Therefore the initial value of the linear relationship is 5.
Answer:
1
Step-by-step explanation:
Two ordered pairs that can be seen are (0,1) and (1,2)
Using delta y/ delta x,
(2-1)/(1-0) = slope
slope = 1/1
slope = 1
As written, the denominator in both fractions is x, so the only restriction on the domain is ... x ≠ 0.
_____
We suspect you intend ...
... f(x) = 2/(x-4) +1/(x+2)
which is undefined when x = 4 or x = -2.
The domain is all real numbers except -2 and 4.
Answer:
x = 15°
y = 59°
Step-by-step explanation:
Angles at a right angle add up to 90°
41 + y = 90
y = 90 - 41
y = 59°
Angles in a triangle add up to 180°
41 + (2x - 9) + 7x + 13 = 180
41 + 13 - 9 + 2x + 7x = 180
45 + 9x = 180
9x = 180 - 45
9x = 135
x = 135/9
x = 15°
Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).