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3 years ago

Explain why a graph that fails the vertical-line test does not represent a function

1 answer:

5 0

For any given y value, there can only be one x value. Let's consider a graph with a line that curves and intersects x=2 twice. This would mean that if you plug 2 into the function you would get two answers. However, this is not possible as plugging in any value to x will result in only one answer. For example, if y= 4x + 3, no matter how many times I plug a number in there, I'm always going to get the same y value, and this is true for all real functions.

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HEP MAKE INTO A DECIMAL!!!!

Korvikt [17]

Answer:

2.25

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The government of Preon (a small island nation) was voted in at the last election with 58% of the votes. That was 2 years ago, a

mel-nik [20]

Answer:

a) $z=\frac{0.684 -0.58}{\sqrt{\frac{0.58(1-0.58)}{114}}}=2.250$

b) $p_v =2*P(z>2.250)=0.0244$

If we compare the p value and the significance level given we see that $p_v$ we have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Data given and notation

n=114 represent the random sample taken

$\hat p=0.684$ estimated proportion of people that their approval rating might have changed

$p_o=0.58$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Hypothesis

We need to conduct a hypothesis in order to test the claim that true proportion of people that their approval rating might have changed is 0.58 or no.:

Null hypothesis: $p=0.58$

Alternative hypothesis: $p \neq 0.58$

Part a

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.684 -0.58}{\sqrt{\frac{0.58(1-0.58)}{114}}}=2.250$

Part b: Statistical decision

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.250)=0.0244$

If we compare the p value and the significance level given we see that $p_v$ we have enough evidence to reject the null hypothesis at 5% of significance.

7 0

2 years ago

Help !!! What is the equivalent exponential expression for the radical expression below

tangare [24]

Answer:

A. $\huge \purple { {(2 + 6)}^{ \frac{1}{2} } }$