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Grace [21]
3 years ago
8

Assume that when adults with smartphones are randomly​ selected, 46​% use them in meetings or classes. If 9 adult smartphone use

rs are randomly​ selected, find the probability that exactly 3 of them use their smartphones in meetings or classes.
Mathematics
1 answer:
MArishka [77]3 years ago
8 0

Answer:

0.2027 is the probability that exactly 3 out of 9 adults use their smartphones in meetings or classes.

Step-by-step explanation:

We are given the following information:

We treat adult using smartphones in meetings or classes as a success.

P(Adult using smartphone) = 46% = 0.46

Then the number of adults follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 9

We have to evaluate:

P(x = 3)\\\\= \binom{9}{3}(0.46)^3(1-0.46)^6\\\\= 0.2027

0.2027 is the probability that exactly 3 out of 9 adults use their smartphones in meetings or classes.

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-2x + 3 < 5 Show your work/steps
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<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

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