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Yuki888 [10]
3 years ago
12

The table below summarises the number of books in some students' schoolbags.

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

Total number of students = 50 students.

Step-by-step explanation:

Total number of books = number of books * frequency

1 * 3 = 3

2 * 5 = 10

3 * 12 = 36

4 * 25 = 100

5 * 4 = 20

6 * 1 = 6

Total number of books = 3 + 10 + 36 + 100 + 20 + 6

Total number of books = 175 books.

Now, to find the total number of students;

Total number of students = summation of frequency

Total number of students = 3 + 5 + 12 + 25 + 4 + 1

Total number of students = 50 students.

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Nora's paper airplane flew 9 1/6 feet. That was 2 3/4 feet farther than Max's plane flew. Write and solve an equation to show ho
stepan [7]

Answer:

Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

Step-by-step explanation:

As Nora's paper airplane flew 9 1/6 feet

i.e.

9\frac{1}{6}=\frac{55}{6}

Nora's paper was farther than Max's plane flew by = 2 3/4 feet

i.e.

2\frac{3}{4}=\frac{11}{4}

Thus the equation to show how far Max's paper airplane flew is:

\:\:9\frac{1}{6}-2\frac{3}{4}

=\frac{55}{6}-\frac{11}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

=\frac{110}{12}-\frac{33}{12}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{110-33}{12}

\mathrm{Subtract\:the\:numbers:}\:110-33=77

=\frac{77}{12}

=6\frac{5}{12}

Therefore, Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

6 0
3 years ago
If y varies directly as x^2 and y=12 when x=2, find y when x=5
Shkiper50 [21]
y=ax^2\\\\y=12\ \ \ and\ \ \ x=2\ \ \ \Rightarrow\ \ \ 12=a\cdot 2^2\ \ \ \Rightarrow\ \ \ a= \frac{4}{12}= \frac{1}{3}  \\\\y=\frac{1}{3} x^2\\\\x=5\ \ \ \Rightarrow\ \ \ y=\frac{1}{3} \cdot5^2=\frac{25}{3} =8\frac{1}{3}
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Answer:

X= 75, Y=30 there you go!

Step-by-step explanation:

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