What is the area of this figure?
2 answers:
The area of the given figure is 114.8 sq cm.
Step-by-step explanation:
Given,
The figure consists of a right angle triangle, a rectangle and a parallelogram
Area of the fig = area of triangle + area of rectangle + area of parallelogram
<u>For the triangle</u>
Height (h) = 4.5 cm
Base (b) = 11.2 cm
<u>For the rectangle</u>
Length (l) = 8 cm
Width (w) = 4.5 cm
<u>For the parallelogram</u>
Length of opposite parallel side (b) = 8 cm
Height (h) = 6.7 cm
To find the area of the figure.
Formula
Area of triangle = ×b×h
Area of rectangle = l×w
Area of parallelogram = b×h
Now,
Area of triangle = ×11.2×4.5 sq cm
=25.2 sq cm
Area of rectangle = 8×4.5 sq cm = 36 sq cm
Area of parallelogram = 6.7×8 sq cm = 53.6 sq cm
Hence,
Area of the fig = 25.2+36+53.6 sq cm = 114.8 sq cm
Answer:
114.8 cm^2
Step-by-step explanation:
<h2><u>Finding the area of the shape </u></h2>we can break down this figure into individual shapes :
- rectangle
- triangle
- parallelogram
<h3><u>area of a triangle</u></h3>formula:
<u>area of a triangle =25.2 cm^2</u>
<u />
<h3><u>area of a rectangle</u></h3>formula:
4.5 * 8
<u>area of a rectangle = 36 cm^2</u>
<u />
<h3><u>area of parallelogram</u></h3>formula:
1/2 * ( sum of parallel sides ) * height
1/2 * ( 8 + 8 ) * 6.7
<u>area of a parallelogram = 53.6 cm^2</u>
<u />
<h3><u>Total area</u></h3>= area of rectangle + area of triangle + area of parallelogram
= 25.2 + 36 + 53.6
<h2><u>= 114.8 cm^2</u></h2>You might be interested in
Answer:
See below description.
Step-by-step explanation:
The function has the following characteristics:
- Factors:
- Zeros/roots: x=0, x=-2, amd x=1
- Positive leading coefficient
- Graph starts up, curves down through -2 on the x-axis and back up to 0 where it touches and curves down and back up again again. It comes down back through 1 and crosses.
- Its graph s the shape of a W.
- It has minimum values at -2.83 and -0.397
Answer:
(x-2)(x+3)(x+6)
Step-by-step explanation:
Given the polynomial function p(x)=x^3+7x^2-36
We are to write it as a product of its linear factor
Assuming the value of x that will make the polynomial p(x) to be zero
Let x = 2
P(2) = 2³+7(2)²-36
P(2) = 8+7(4)-36
P(2) = 8+28-36
P(2) = 0
Since p(2) = 0 hence x-2 is one of the linear factors
Also assume x = -3
P(-3) = (-3)³+7(-3)²-36
P(-3) = -27+7(9)-36
P(-3) = -27+63-36
P(-3) = 36-36
P(-3) = 0
Since p(-3) = 0, hence x+3 is also a factor
The two linear pair are (x-2)(x+3)
(x-2)(x+3) = x²+3x-2x-6
(x-2)(x+3) = x²+x-6
To get the third linear function, we will divide x^3+7x^2-36 by x²+x-6 as shown in the attachment.
x^3+7x^2-36/x²+x-6 = x+6
Hence the third linear factor is x+6
x^3+7x^2-36 = (x-2)(x+3)(x+6)
