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2 years ago

Write 1/1000 as a power of 10 using negative exponents.

Mathematics

1 answer:

Anna007 [38]2 years ago

5 0

Answer:

${10}^{ - 3}$

Step-by-step explanation:

$\frac{1}{1000} = \frac{1}{ {10}^{3} } = {10}^{ - 3}$

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Need help on this one please answer asap

Vanyuwa [196]

15/3 = 5 minutes per customer
48/6 = 8 minutes per customer
30/5 = 6 minutes per customer
This means restaurant 1 was the fastest.

4 0

3 years ago

Factor completely h^3+2h^2-9h-18

guapka [62]

Step 1: Group this into two groups:

$h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)$

When you do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

$(h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)$

Step 3: Notice both groups have that (h+2)? That's a new GCF between the two groups, so factor that out:

$h^2 (h+2) -9(h+2) = (h+2)(h^2-9)$

Step 4: That $(h^2-9)$ piece can be factored further, since it's a difference of squares:

$(h+2)(h^2-9) = (h+2)(h+3)(h-3)$

Now it's factored.

8 0

2 years ago

Two candidates are randomly selected. a. List all the possible outcomes. b. What is the probability that both are qualified? c.

steposvetlana [31]

Question:

Four candidates are to be interviewed for a job. Two of them, numbered 1 and 2, are qualified, and the other two, numbered 3 and 4, are not.

Answer:

a. S = {12,13,14,23,24,34}

b. 1/6

c. ⅔

Step-by-step explanation:

Let S = Sample Space i.e. total possible outcomes

Given that candidates 1 and 2 are qualified and 3 and 4 are not qualified.

If two candidates are randomly selected. The list of all possible outcomes is as follows

S:{12,13,14,23,24,34}

And the number of outcomes is 6

b. What is the probability that both are qualified?

The event that both are qualified is given as {12} or {21}

From the sample space in (a) above, there's only one occurrence of {12} = 1

So, the probability is calculated as 1/6

c. What is the probability that exactly one is qualified?

The event that one one is qualified is given as {13,14,23,24}

Total = 4

Probability = 4/6

Probability = ⅔

5 0

3 years ago

A Cell Phone company sells cellular phones and airtime in a State. At a recent meeting, the marketing manager states that the av

GarryVolchara [31]

Answer:

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

The sample does not support the manager claim (the average age seems to differ from 40 years).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The manager claims that the average age of customers is 40 years. As this is an equality, we will test if the average age differs from 40. If the null hypothesis failed to be rejected, the claim of the manager is right.

Then, the claim is that the average age of the customers differs from 40 years.

Then, the null and alternative hypothesis are:

$H_0: \mu=40\\\\H_a:\mu\neq 40$

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=38.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7}{\sqrt{50}}=0.99$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{38-40}{0.99}=\dfrac{-2}{0.99}=-2.02$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

This test is a two-tailed test, with 49 degrees of freedom and t=-2.02, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t$

As the P-value (0.049) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

3 0

3 years ago

If fx = 2x^2 + 3 and g(x) = x^2 - 7 find (f - g) (x)

Semmy [17]

(f-g) (x) means to subtract g(x) from f(x)

F(x) = 2x^2 +3

g(x) = x^2

This becomes:

2x^2 + 3 - x^2 = x^2 +3

3 0

3 years ago