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Scrat [10]
2 years ago
5

The question is in the image inserted below

Mathematics
1 answer:
neonofarm [45]2 years ago
5 0

Answer:

median is 75 and range is 45

Step-by-step explanation:

range is largest number - smallest number so 95-50=45

Median is the medium of all the data. The medium is shown by the middle line in the box portion of the plot.

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What is the unit rate for 4543.08 km in 52.4 h? Enter your answer, as a decimal, in the box. km/h
sdas [7]
Plz mark me brainliest the answer is 86.7

hope this helps :)


8 0
3 years ago
Read 2 more answers
Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha
san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

P(L U H) + 0.10P(L U H) = 0.26

This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0
2 years ago
HELP 1 QUESTION!! IREADY!!! EXPLAIN!!
Anit [1.1K]
The linear equation (y = mx + b) for this particular line is d = 0.6t
it's the same as finding the equation for any line except they use d instead of y and t instead of x. The slope m is 0.6 and intercept is zero.
4 0
3 years ago
Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples
zheka24 [161]

Answer: a. 0.40   b. 0.23  c . 0.435   d . 0.25

Step-by-step explanation:

                                   melanin      content    Total

                                            high   low

moisture   high                     13      10                23

content    low                       47      30                77

 Total                                   60      40              <u> </u><u>100</u>

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)=\dfrac{40}{100}=0.40

b) Total skin samples has high moisture content = 13+10=23

P(B) =\dfrac{23}{100}=0.23

c) A ∩ B =  Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) =\dfrac{10}{100}=0.10

Using conditional probability formula , P (A|B)=\dfrac{P(A\cap B)}{P(B)}

P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435

d)  P (B|A)=\dfrac{P(A\cap B)}{P(A)}

P (B|A)=\dfrac{0.10}{0.40}=0.25

8 0
3 years ago
Would it be 1/5 ?? i'm not sure how to do probability
Sidana [21]

Answer:

Choice A

Step-by-step explanation:

5 red socks, 2 white socks, 3 blue socks = 10 socks


1 st sock red : 5 / 10

2nd sock red : 4/9

we didn't put the sock back

a pair of red socks

5/10 * 4/9 = 20/90 = 2/9



8 0
3 years ago
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