Plz mark me brainliest the answer is 86.7
hope this helps :)
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
The linear equation (y = mx + b) for this particular line is d = 0.6t
it's the same as finding the equation for any line except they use d instead of y and t instead of x. The slope m is 0.6 and intercept is zero.
Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25
Step-by-step explanation:
melanin content Total
high low
moisture high 13 10 23
content low 47 30 77
Total 60 40 <u> </u><u>100</u>
Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.
a) Total skin samples has low melanin content = 10+30=40
P(A)=
b) Total skin samples has high moisture content = 13+10=23
P(B) =
c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10
P(A ∩ B) =
Using conditional probability formula , 
d) 
Answer:
Choice A
Step-by-step explanation:
5 red socks, 2 white socks, 3 blue socks = 10 socks
1 st sock red : 5 / 10
2nd sock red : 4/9
we didn't put the sock back
a pair of red socks
5/10 * 4/9 = 20/90 = 2/9
