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STALIN [3.7K]
3 years ago
6

24% as a fraction simplifying it as far as posible

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0
p\%=\dfrac{p}{100}\\\\24\%=\dfrac{24}{100}=\dfrac{24:4}{100:4}=\dfrac{6}{25}
gregori [183]3 years ago
4 0
Since 24% is out of 100%, we can start with the fraction 24/100 and start simplifying:
24/100    
12/50
6/25
Now, the factors of 6 besides 1 are 2, 3, and 6.  25 is not evenly divisible by any of these, so the fraction is 6/25.
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At 107°F, a certain insect chirps at a rate of 92 times per minute, and at 113°F, they chirp 116 times per minute. Write an equa
dsp73

Answer:

The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.

Step-by-step explanation:

A linear equation can be expressed in the form y=m*x + b. In this equation, x and y are coordinates of a point, m is the slope and b is the y coordinate of the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

When there are two points of a line (x1, y1) and (x2, y2), the slope is determined by the quotient between the difference of the ordinate of these two points and the difference of the abscissa of the same points. This is:

m=\frac{y2-y1}{x2-x1}

Having a point on the line, you can substitute the values ​​of m, x and y in the equation y = mx + b and thus find b.

In this case:

  • (x1, y1): (92, 107)
  • (x2, y2): (116, 113)

So:

m=\frac{113-107}{116-92}

m= 0.25

substituting the values ​​of m, x1 and y1 in the equation y = mx + b you have:

107= 0.25*92 + b

107 - 0.25*92= b

84=b

<u><em>The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.</em></u>

3 0
3 years ago
On the scale drawing of a car, the length from bumper to bumper is 6 inches. The car’s actual length, from bumper to bumper, is
Softa [21]

Answer:

6. 16

12. 32

18. 48

24. 64

6 0
3 years ago
Find the length of a diagonal<br> of a square with sides of 14<br> feet long.<br> [?][feet<br> /
inessss [21]

Answer:

14√2 feet

Step-by-step explanation:

The length of a diagonal of a square is L=S\sqrt{2} where S is the side length of the square. Therefore, L=14\sqrt{2}.

4 0
3 years ago
A bakery bakes 2000 loaves in 5 hours . How many loaves will be baked in 12​
Kisachek [45]

Answer:

4,800 loaves.

Step-by-step explanation:

Solve by utilizing ratios and cross-multiplication.

8 0
3 years ago
Read 2 more answers
A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack
adelina 88 [10]

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

6 0
4 years ago
Read 2 more answers
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