Answer:
Each student ticket costs $8.33
Each adult ticket costs $15.34
Step-by-step explanation:
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?
s = cost of each student ticket
a = cost of adult ticket
Our system of equations:
4s + 2a = 64
3s + 3a = 71
-3(4s + 2a = 64) ==> -12s - 6a = -192
2(3s + 3a = 71) ==> 6s + 6a = 142
-12s - 6a = -192
6s + 6a = 142
-6s = -50
/-6 /-6
s = $8.33 (the cost of each student ticket)
Now, let's find the cost of each adult ticket:
4s + 2a = 64
4(8.33) + 2a = 64
33.32 + 2a = 64
-33.32 -33.32
2a = 30.68
/2 /2
a = 15.34 (the cost of each adult ticket)
(x, y) ==> (8.33, 15.34)
Check your answer:
4s + 2a = 64
4(8.33) + 2(15.34) = 64
33.32 + 30.68 = 64
64 = 64
This statement is true
Hope this helps!
Answer:
4090 ml - 4.9L
1.4km - 4901m
Step-by-step explanation:
A liter is made up of 1000 ml so 4.9 l is equvilant to 4,900 ml.
A kilometre same as litre is made up of a 1000 m. So 1.4 km is 1400m
However, ml and l is a measurement of volume while m and km is a measurement of distance.
Answer:The cost of one month of game-play =$20
Step-by-step explanation:
Let the cost of one month of gameplay be x
Then cost of game-play bought by Angie =3x.....(1)
and Then cost of game-play bought by Kenny=4x......(2)
Cost of each software package =$50......(3)
The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x
⇒240=100+7x.......→(by adding like terms)
⇒140=7x⇒x=20.....→( dividing both sides by 7 )
∴the cost of one month of game-play =$20
Answer:
Multiply both sides of the equation
Step-by-step explanation:
The rule for multiplying similar bases with exponents is:
(a^b)*(a^c)=a^(b+c)
In this case you have:
(x^9)(x^2)
x^(9+2)
x^11