Answer:
-128 it’s on the table
Step-by-step explanation:
Answer:
The answer is -6.
Step-by-step explanation:
To find the value of y in (3, y), plug in 3 for x in y = -(2x) and solve for y.
y = -(2(3))
y = -6
y = -6, so the answer is -6.
Answer: 0.1824
Step-by-step explanation:
Given : The mileage per day is distributed normally with
Mean : 
Standard deviation : 
Let X be the random variable that represents the distance traveled by truck in one day .
Now, calculate the z-score :-

For x= 132 miles per day.

For x= 159 miles per day.

Now by using standard normal distribution table, the probability that a truck drives between 132 and 159 miles in a day will be :-

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824
The answer would be 4:5 because they said basketballs first