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3 years ago

Solve for h: 10h + 2 = 32

2 answers:

7 0

You subtract 2 from both sides and after +2-2= 0 32-2=30 After you take 10h = 30 And then you divided by ten 10/10 = 1 30 divided by 10 is 3. So. H = 3

Leokris [45]3 years ago

5 0

Subtract 2 on both sides, 32 minus 2 is 30 then divide 10 which gives h=3

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Solve for y. <br> y^2-xy+3=-xy+y^2

IRISSAK [1]

The answer for your question is 0=-3

3 0

3 years ago

You need 200 mL of a 10% alcohol solution. On hand, you have a 25% alcohol mixture. How much of the 25%

Anastasy [175]

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4 0

2 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

2 years ago

Six out 8 teachers prefer expo markers to non bran markers. What is the ratio of teachers who do not prefer expo markers to thos

Sauron [17]

Answer:

2 to 6

Step-by-step explanation:

If 6 teachers prefer expo markers then 6-8=2 then there are two teachers that don't prefer markers and 6 that do so the equals 2:6

6 0

2 years ago

Read 2 more answers

Solve the right triangle. Round decimals to the nearest tenth

LekaFEV [45]

Answer: 42

Step-by-step explanation:

angle t is 42 degrees

5 0

1 year ago

Solve for h: 10h + 2 = 32​

Solve for h: 10h + 2 = 32