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Nataliya [291]
3 years ago
11

What is y-intercept of the line described by the equation below? y = 5x-22

Mathematics
2 answers:
saveliy_v [14]3 years ago
7 0

In order to calculate the y-intercept of the line described by the equation

y = 5x -22, we have to put x = 0. This is because y-intercept represents the point at which the straight line crosses the y-axis.

If we put x = 0, then 5x becomes 5 x 0 = 0

Therefore, the equation becomes, y = 0 - 22

For this reason, the y-intercept of the line is y = -22.

erastova [34]3 years ago
5 0

Answer:

it would be 5 (a p e x )

Step-by-step explanation:

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What is an equation that passes through the point (-2,-3) and is parallel to the line 5x+2y=14
Alekssandra [29.7K]

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One of the legs of a right triangle measures 7 cm and its hypotenuse measures 12 cm.
Oksana_A [137]

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AC ≈ 9,7sm

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\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

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