Answer:
Determination of HYP,OPP,ADJ with respect to x.
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>
<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>
Answer:

Hope this helps! If you need an explanation, I've got you.
Answer:
AC ≈ 9,7sm
Step-by-step explanation:
AB=7 One side of a right triangle
BC=12 Hypotenuse of a right triangle
AC=?=x The other side of a right triangle
x²+7²=12²
x²=144-49
x²=95
x=√(95) ≈ 9,7
AC ≈ 9,7sm
The answer is c. You double the number for finding radius