Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward.
So, y-5 = (x-2)²
Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum)
The domain (x- value) is all Real { x|x = -∞ to x=+∞}
The Range (y-value) is all y ≥ 5
Slope formula : (y2 - y1) / (x2 - x1)
(4,1)...x1 = 4 and y1 = 1
(-1,-5)...x2 = -1 and y2 = -5
now we sub and solve
slope = (-5 - 1) / (-1 - 4) = -6/-5 = 6/5 <==
Answer:
13.2
Step-by-step explanation:
301=3n+1
solve for n, if it is a natural number (1,2,3,4,5...) then it is in the sequence
301=3n+1
minus 1
300=3n
divide 3
100=n
yes it is
it is the 100th term