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Licemer1 [7]
3 years ago
6

2(4x - 5) - (x - 4) solve please

Mathematics
2 answers:
icang [17]3 years ago
7 0

Step-by-step explanation:

2(4x-5) - (x-4)

8x-10 - (x-4)

8x-10 -x+4

7x-6

zmey [24]3 years ago
4 0

Answer:

7x-6

Step-by-step explanation:

2(4x-5)-(x-4)

8x-10-x-(-4)

8x-10-x+4

7x-10+4

7x-6

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4 years ago
Write an equation parallel to y=3x+6 that passes through the point (4, 7)
HACTEHA [7]

Answer:

y = 3x - 5

Step-by-step explanation:

The equation of a line parallel to y=3x+6 has exactly the same form but a different constant on the right:  y=3x+C

To find C, take the coordinates of the given point and substitute them into y=3x+C:

7 = 3(4) + C, or

7 = 12 + C, and so C = -5

The desired equation is y = 3x - 5

5 0
3 years ago
Ramesh marks 48,56,98 what is average
gizmo_the_mogwai [7]

Answer:

Ramesh scores about 67.3

Step-by-step explanation:

To find average we need add all the numbers and divide by the number of numbers so:

48+56+98=202

202/3= 67.333

67.33%

4 0
3 years ago
10 is multiplied by the sum of 3 and 2. The product is divided by 2, and then 5 is added in numerical expression
bija089 [108]
30 is your answer to this problem

7 0
3 years ago
Read 2 more answers
Please answer this question (10) GIVING BRAINLIEST!!
sweet [91]
<h3>Answer:  y = 5</h3>

==============================================================

Explanation:

For any rectangle, the diagonals are always the same length. We can use congruent triangles to prove this.

This means AC = BD.

Also, the diagonals of a rectangle cut each other in half (bisect). This indicates the following two equations

  • AP = PC
  • BP = DP

We'll use that second equation along with BP = -2x+23 and DP = 3y-6 to form the equation -2x+23 = 3y-6. This will be used later.

---------------

By the segment addition postulate, we know that

BP+DP = BD

(-2x+23)+(3y-6) = BD

BD = -2x+3y+17

Since the diagonals are equal, we also know that AC = -2x+3y+17

We are given that AC = 2x+4

Equating the two right hand sides leads to the equation 2x+4 = -2x+3y+17

---------------

The conclusion of each the last two sections was the following two equations

  • -2x+23 = 3y-6
  • 2x+4 = -2x+3y+17

We have two equations and two unknowns. We have enough info to be able to find x and y.

Let's isolate 3y in the first equation

-2x+23 = 3y-6

3y-6 = -2x+23

3y = -2x+23+6

3y = -2x+29

Then we can plug this into the second equation

2x+4 = -2x+3y+17

2x+4 = -2x+(3y)+17

2x+4 = -2x+(-2x+29)+17 .... replace 3y with -2x+29

Now solve for x

2x+4 = -2x+(-2x+29)+17

2x+4 = -2x-2x+29+17

2x+4 = -4x+46

2x+4x = 46-4

6x = 42

x = 42/6

x = 7

We then use this to find y

3y = -2x+29

3y = -2(7)+29

3y = -14+29

3y = 15

y = 15/3

y = 5

4 0
3 years ago
Read 2 more answers
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