Answer:
Step-by-step explanation:
From the question we are told that:
Center of hyperbola at ( 6 , 9 )
Focus of hyperbola at ( 11 , 9 )
Vertex of hyperbola at ( 9 , 9)
Equation of hyperbola
Generally the C and D of the hyperbola equation is mathematically given by
Generally the A and B a of the hyperbola equation is mathematically given by
Therefore with Center,Focus ,Vertex on the same line
A. is not true.
B. is true.
C. is not true.
D. is not true.
Hope it helped
BioTeacher101
Answer:
-3x² - 10x - 16 r.
Step-by-step explanation:
You can easily do this through synthetic division:
First step is to get all the numeric coefficients of the expression and write them down. Don't forget to bring their signs along with them.
-3x³ - 4x² + 4x +3
| -3 -4 +4 +3
|______________
Next we find the root that is associated with the divisor:
x - 2 = 0
x = 2
We use this and put it outside:
2 | -3 -4 +4 +3
|______________
Okay now we bring down the first coefficient:
2 | -3 -4 +4 +3
|______________
-3
Then we multiply it by the root and put the product under the next coefficient:
2 x - 3 = -6
2 | -3 -4 +4 +3
|<u> -6 </u>
-3
Then we add them:
2 | -3 -4 +4 +3
|<u> -6 </u>
-3 -10
Do the same steps until the end:
2 | -3 -4 +4 +3
|<u> -6 -20 -32 </u>
-3 -10 -16 -29
Now that you have that, remember that since the divisor is in the 1st degree, quotient will have a degree will be one degree below as well.
-3x² - 10x - 26
Your last coefficient is going to be your remainder:
-3x² - 10x - 16 r.