Rewrite 14 1/3 as an improper fraction

a group of 10 people ran an average of 2.7 miles in one week. if the first 4 people in the group averaged 3 miles, what did the

FromTheMoon [43]

In this question, 10 people average running distance is 2.7miles. Then the sum of their running distance would be: 10 people * 2.7 miles/people= 27 miles.

The group then divided into 2, 4 people with 3 miles average and 6 people with unknown average. Since the people are same like the 10 people group, their total running distance would be the same. The calculation would be:

total distance = group1 * average1 + group2 * average2
27 miles= 4 people * 3 miles/people + 6 people* average2
6 people * average2 = 27 miles -12 miles = 15 miles
average2= 15 miles/6people= 2.5 miles/people

4 0

3 years ago

Answer it answer it answer it

Troyanec [42]

Answer:

22.5

Step-by-step explanation:

cause

8 0

3 years ago

Read 2 more answers

The houck family's train traveled 552 miles in 6 hours. The Roberts family traveled at 744 miles in 8 hours which family is trav

rusak2 [61]

Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.

Step-by-step explanation: Speed of Houck family's train = 552m/6hrs

speed of Robert family's train = 744m/8hrs.

Therefore considering Houck speed,

552miles = 6hours

1mile = (6 x 60)/552

= 360/552

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

For Robert

744miles = 8hours

1mile = ( 8 x 60 )/744

= (480/744)minutes

= 0.645

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

Conclusion: Both families were travelling at the same speed/rate.

To get that minutes in hour, just divide by 60 to get concert to hours.

6 0

3 years ago

3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d

pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
$\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}$

Where A is the final amount, P is the initial amount, r is the interest rate, n is the number of times compounded per year, and t is the number of years.

To obtain $4000 after two years, let A = 4000 and t = 2.

Because the account pays 3% interest compounded monthly, r = 0.03 and n = 12.

Substitute and solve for P:

$\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}$

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

$\displaystyle A = Pe^{rt}$

Where e is Euler's number.

Hence, let A = 4000, r = 0.04 and t = 2. Substitute and solve for P:

$\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}$

In conclusion, about $3692.47 should be deposited.

8 0

2 years ago

Based on the sample of 500 people, 42% owned cats. Calculate the test statistic. Round to two decimal places.

Tanzania [10]

Answer:

z= 3.63

z for significance level = 0.05 is ± 1.645

Step-by-step explanation:

Here p = 42% = 0.42

n= 500

We formulate our null and alternative hypotheses as

H0: p= 0.42 against Ha : p> 0.42 One tailed test

From this we can find q which is equal to 1-p= 1-0.42 = 0.58

Taking p`= 0.5

Now using the z test

z= p`- p/ √p(1-p)/n

Putting the values

z= 0.5- 0.42/ √0.42*0.58/500

z= 0.5- 0.42/ 0.0220

z= 3.63

For one tailed test the value of z for significance level = 0.05 is ± 1.645

Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.

4 0

3 years ago