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Yuri [45]
3 years ago
13

PLEASE HELPPPPPPPPPP!!!!!!!!!

Mathematics
1 answer:
Ivan3 years ago
7 0

Answer:

11a^2b^8

Step-by-step explanation:

Rule 1: The coefficient (121 in this case) has it's square root taken to derive the side.

Rule 2: If a variable with a power is part of the area of  a square, then just divide the power by two

The square root of 121 = 11

The square root of a^4 = a^(4/2) = a^2

The square root of b^16 = b^(16/2) = b^8

You might be interested in
Andy joins a social networking site. After day three, he has 25 friends; after day eight, he has 40 friends. Write the equation
Allisa [31]

Answer:

Point slope intercept form: The equation for line is given by; y-y_1=m(x-x_1) ......[1] ; where m is the slope and a point (x_1, y_1) on the line.

Let x represents the number of days and y represents the number of friends.

As per the statement:  After day three, he has 25 friends; after day eight, he has 40 friends.

⇒ We have two points i.e,

(3, 25) and (8, 40)

First calculate slope(m);

m = \frac{y_2-y_1}{x_2-x_1}

Substitute the given values we get;

m = \frac{40-25}{8-3}=\frac{15}{5} = 3

now, substitute the given values of m=3 and a point (3, 25) in [1] we get;

y-25=3(x-3)

Using distributive property; a \cdot(b+c) = a\cdot b + a\cdot c

y-25 = 3x - 9

Add 25 on both sides, we get;

y-25+25 = 3x - 9+25

Simplify:

y =3x + 16

if  x = 18 days, then;

y = 3(18) + 16 = 54+16 = 70

Therefore, he will have on day 18, if he continues to add the same number of friends each day is, 70 friends.

7 0
3 years ago
Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3
VashaNatasha [74]
  The correct answer is:  Answer choice:  [A]:
__________________________________________________________
→  "\frac{u}{u-3} " ;  " { u \neq ± 3 } " ; 

          →  or, write as:  " u / (u − 3) " ;  {" u ≠ 3 "}  AND:  {" u ≠ -3 "} ; 
__________________________________________________________
Explanation:
__________________________________________________________
 We are asked to simplify:
  
  \frac{(u^2+3u)}{(u^2-9)} ;  


Note that the "numerator" —which is:  "(u² + 3u)" — can be factored into:
                                                      →  " u(u + 3) " ;

And that the "denominator" —which is:  "(u² − 9)" — can be factored into:
                                                      →   "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→    \frac{u(u+3)}{(u-3)(u+3)}  ;

___________________________________________________________

→  We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" \frac{(u+3)}{(u+3)} = 1 "  ;

→  And we have:
_________________________________________________________

→  " \frac{u}{u-3} " ;   that is:  " u / (u − 3) " ;  { u\neq 3 } .
                                                                                and:  { u\neq-3 } .

→ which is:  "Answer choice:  [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ; 

and if the denominator is "(u − 3)" ;  the denominator equals "0" when "u = -3" ;  as such:

"u\neq3" ; 

→ Note:  To solve:  "u + 3 = 0" ; 

 Subtract "3" from each side of the equation; 

                       →  " u + 3 − 3 = 0 − 3 " ; 

                       → u =  -3 (when the "denominator" equals "0") ; 
 
                       → As such:  " u \neq -3 " ; 

Furthermore, consider the initial (unsimplified) given expression:

→  \frac{(u^2+3u)}{(u^2-9)} ;  

Note:  The denominator is:  "(u²  − 9)" . 

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ; 

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________ 

→  " u² − 9 = 0 " ; 

 →  Add "9" to each side of the equation ; 

 →  u² − 9 + 9 = 0 + 9 ; 

 →  u² = 9 ; 

Take the square root of each side of the equation; 
 to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ; 

→ √(u²) = √9 ; 

→ | u | = 3 ; 

→  " u = 3" ; AND;  "u = -3 " ; 

We already have:  "u = -3" (a value at which the "denominator equals "0") ; 

We now have "u = 3" ; as a value at which the "denominator equals "0"); 

→ As such: " u\neq 3" ; "u \neq -3 " ;  

or, write as:  " { u \neq ± 3 } " .

_________________________________________________________
6 0
3 years ago
And also this question as well
gtnhenbr [62]

Answer:

It's the second one I believe, because it's not a straight line, and nearly all functions have curved lines

Step-by-step explanation:

4 0
3 years ago
A tomato plant grows 24 inches tall in 10 weeks. If the rate remains the same, how tall would the plant be after 7 weeks?
joja [24]

Answer:

168 inches which is also 14 feet

3 0
3 years ago
I dont know how to do this. I know the answer is -3 but I dont know how I dont understand
monitta

Answer:

2

Step-by-step explanation:

PEMDAS

parenthesis

, exponents,

multiplication,

division,

addition,

subtraction.

6 0
3 years ago
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