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horrorfan [7]
3 years ago
7

The heartworms that can accumulate within the hearts of dogs and other mammals have a pseudocoelom, an alimentary canal, and an

outer covering that is occasionally shed. To which phylum does the heartworm belong? a. Platyhelminthes b. Annelida c. Arthropoda d. Nematoda
Biology
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

Nematode.

Explanation:

Heartworms belongs to phylum Nematoda, their biological name is Dirofilaria immitis. Their body structure is a tiny thread-like parasite roundworm. Adult heartworms always live in the lung arteries and the heart of the dogs and other mammals, it can spread from one species to another by the mosquito bites. Some characteristics of Nematoda phylum are:

1) Their body structure is triploblastic, bilaterally equal and cylindrical in shape.

2) They show a tissue-level organization.

3) Their body keeps a pouch or pseudocoelom.

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6 0
3 years ago
Pseudomonas putida is used for fermentation of the lactose present in cheese whey. The bacteria are cultivated in a steady-state
fgiga [73]

Answer:

Explanation:

Given that:

The dilution rate D = 0.28 h⁻¹

The concentration of lactose in the feed S_o = 2.0 \ g/L

The effluent S = 0.10 g/L

Also;

Y_{X/S} = 0.45 g\  X/g  \ S , \\ \\  Y_{X/O2  }= 0.25 g  \ X/g  \ O2,  \\ \\

Saturation C* = 8 mg/l

To calculate the steady-state biomass, we use the formula:

X = Y_{X/S}(S_o-S_e) \\ \\ X = 0.45(2.0 -0.10) \ g/L \\ \\ X= 0.45 (1.9) \ g/L \\ \\  X = 0.855\ g/L \\ \\  X = 855 \ mg/L

The biomass is 0.855 g/L

For a steady-state condition, the oxygen uptake rate can be illustrated by using the formula:

q_{o_2}X =\dfrac{\mu_X}{Y_{X/O_2}}

where;

\mu = dilution rate (D)

Thus, the steady-state can be expressed as:

q_{o_2}X =\dfrac{D}{Y_{X/O_2}}

q_{o_2}X =\dfrac{0.28}{0.25}

q_{o_2}X =1.12 \ h^{-1}

The specific rate of oxygen consumption q_{o_2}X =1.12 \ h^{-1}

b)

In the fermentation medium, if the desired DO concentration C_L = 2 mg/L

Here, the oxygen transfer is regarded as the rate-limiting step.

As such, the oxygen transfer rate(OTR) is equivalent to the oxygen uptake rate.

In this scenario, let's determine the oxygen transfer coefficient (K_{La}) by using the formula:

OTR =  K_{La}(C^* - C_L)

where;

K_{La}= coefficient of oxygen transfer

C* = saturation

Since OTR = q_{O_2}X

q_{o2}X = K_{La}(C^*-C_L) \\\\ (1.12 )(855) = K_{La}(8-2) \\ \\  957.6 = K_La (6) \\ \\ K_{La}= \dfrac{957.6}{6} \\ \\ K_{La} = 159.6 \ h^{-1}

Thus, the oxygen transfer coefficient K_{La} = 159.6 h⁻¹

4 0
3 years ago
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