Answer:
Herbivore
Step-by-step explanation:
The mouse isnt a producer because he cannot make his own food
The mouse isnt a carnivore because he isnt eating meat
The mouse isnt a decomposer because he isnt breaking down dead or decaying organisms
Herbivores are animals that eat vegetables or greens/plants but not meat.
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
z-statistic
Step-by-step explanation:
We have to identify the correct test statistic to use with the given conditions.
- If the sample size is larger than 30, then the sample is considered to be large.
- We are given a sample size of 51, which is a a large sample.
- Also, the population standard deviation is known.
- Thus, we use the z-statistic when testing a hypothesis about a single mean.
- Formula:
where 
is the sample mean, 
is the population mean, 
is the population standard deviation and n is the sample size.
