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2 years ago

How much would you make for one month (4 weeks) if you worked a 40 hour week?

Mathematics

2 answers:

Anon25 [30]2 years ago

7 0

Answer:

Unclear

Step-by-step explanation:

I believe we need more information to solve the problem!

We currently have:

a = b

b = total amount for 40 hours

As you can see, we cannot solve this. For a we would need something like how much you make per week, etc!

Kisachek [45]2 years ago

7 0

X=4hrs. X=4weeks. 2(4x4)=?

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Umm it’s to question just label it a and b

xxMikexx [17]

A) Scale of map is 1: 30,000

This is assuming that it meant 1 centimetre = 30,000 metres, for it gives no other information.

Multiply 1 with 30,000: 30,000 x `1 = 30,000

30,000 metres is your answer.

B) Scale is 1 inch: 6 miles. You are given 2.5 inches.

Remember that 1 inch = 6 miles.

Multiply 2.5 to both sides: (2.5) * 1 inch = (2.5) * 6 miles

2.5 inch = 2.5 * 6 miles

2.5 inch = 15 miles

15 miles is your answer.

3 0

3 years ago

Read 2 more answers

HELP<br> Please<br> Please<br> im failing

Reptile [31]

Answer:

6.9

7.-5

8.-10

Step-by-step explanation:

3 0

3 years ago

What is the reason for #2?

NeTakaya

Answer:

I am not sure but i will say C.

Step-by-step explanation:

3 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

The table and the graph each show a different relationship between the same two variables, x and y:

Oksanka [162]

1. y₁ = 70x
2. y₂ = 55x

Solve y₁ - y₂ for x = 11.

8 0

3 years ago