I'm assuming the dimensions are like the measures of whatever the figure is. Volume, length,width,height,circumference,radius,diameter,area,perimeter,etc. whatever you are working with, that will help you find the dimensions of the figure:)
Answer:
Yes
Step-by-step explanation:
A^2+B^2=C^2
11^2+60^2=61^2
121+3600=3721
3721=3721
:)
Answer:
and 
Step-by-step explanation:
A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.
In when x=3, y=15/4≈2.14
In 
when x=3, y=1.8
In when x=3, y≈2.33
In 
when x=3, y≈1.90
We can observe that in two cases, and , y is greater than 2.
Answer:
hope this helps you
option B
Step-by-step explanation:
ecf-zutd-cpt.
Answer:
4 Can I have brainiest me trying to level up
Step-by-step explanation:
Let's make the parenthesis go bye
8-4
so it would be 4
