substitute the ordered pair (2, 3 ) into the 2 equations
(3 × 2 ) + (4 × 3 ) = 6 + 12 = 18 → True
(2 × 2 ) - (2 × 3 ) = 4 - 6 = - 2 → False
Hence the ordered pair (2, 3 ) is not a solution to the system of linear equations.
When (2, 3 ) is substituted into the first equation, the equation is true.
When (2, 3 ) is substituted into the second equation, the equation is false.
Answer:
8
Step-by-step explanation:
The equation for the area of a parallelogram is A=bh. In this case, the base is 4 and the height is two so the equation would be 4*2 which would be eight.
Answer:
C) The solution for the given system of equations are A(0,-5) and B(-4,3)
Step-by-step explanation:
The given system of equation are : 
from equation 2, we get y = -5 - 2x .
Put the above value of y in the equation (1).
We get: 
By ALGEBRAIC IDENTITY:

or, 
or, 
⇒ x = 0 or, x = -20/5 = -4
So, the possible values for x are: x = 0 or x = -4
If x = 0, y = -5-2x = -5-2(0) = -5
and if x = -4, y = -5 -2(-4) = -5 + 8 = 3
Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)
Answer:
y=4
Step-by-step explanation:
I'm a little rusty at this but y=4 should be the correct answer.
Hope this helps!
Five ice cream cones would cost 13.75 at the rate that each cone costs 2.75