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SSSSS [86.1K]
3 years ago
14

Consider a biased coin with the probability of turning up head 0 < p < 1. We flip the coin 10 times and get a sequence of

outcomes: {T, H, H, T, T, H, H, H, T, H}. We know that the probability (likelihood) of observing this sequence.
Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

Probability of obtaining 6H and 4T = 0.2051

Step-by-step explanation:

Since for a fair coin,

Probability of obtaining Head = 0.5

p = 0.5

q = 1-p = 0.5

Probability of obtaining 6H and 4T = 10C6 (p)^6(q)^4 = 210*0.5^6*0.5^4

P(6H, 4T) = 0.2051

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There are 81 red, blue and yellow
wel

Step-by-step explanation:

Here Given

Total counters = 81

red counters are 9 more than the yellow ones.

And Yellow counter = blue counter

So let the Yellow counter be x and as blue counter and yellow counter are same then blue counter will be also x

And by the question

Red counter = 9 + x

Now

9 + x + x + x = 81

9 + 3x = 81

3x = 81 - 9

3x = 72

x = 72 / 3

Therefore x = 24

Now

Red counters = 9 + 24 = 33

Blue counters = 24

Yellow counters = 24

Hope it helped :)

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answer right 2, up 3

any function with the following form is a transformation from f(x) = x²

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2 years ago
write the ratio as a percent 6 per 100 , 49 out of 100 , 16 per 100 , 21 out of 100 , 80 per 100 , 93 out of 100​
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Answer:

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