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2 years ago

Plz help. Will give brainliest

Mathematics

1 answer:

masya89 [10]2 years ago

3 0

Answer:

So is there are 10 cats for every 4 dogs,

If there are 5 cats that is half of 10 so half of 4 is 2

Now there are 32 dogs that is 8 times more than 4 so 10 x 4 is 40 so the answers are

Cats 10 5 8

Dogs 4 2 32

Plz give brainiest

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Given m∠JML = 80 and m∠KML = 33, what is m∠JMK

Harrizon [31]

Answer:

Step-by-step explanation:

Given m∠JML = 80 and m∠KML = 33, to calculate the value of angle m∠JMK, we will apply the formula since all the angles are all acting at point M.

m∠JML = m∠JMK+m∠KML

Substituting the values given into the equation;

80 = m∠JMK + 33

subtract 33 from both sides of the equation

m∠JMK = 80-33

m∠JMK = 47°

<em>Hence the value of angle m∠JMK is 47°</em>

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3 years ago

Alex had 45 toy cars he put 26 toy in a box how many toy cars are not in the box ?

Oksana_A [137]

19 toy cars arent in the box

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3 years ago

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When the product of 0.2 and 0.3 is subtracted from the sun of 0.2 and 0.3 what is the difference

shtirl [24]

(Corrected) Explanation:

(0.2 x 0.3)-(0.2 + 0.3)

0.06 - 0.50

-0.44

Therefore, 0.44 is your answer.

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2 years ago

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Find the values of x and y that make each quadrilateral a parallelogram. Show your work.

Stells [14]

Step-by-step explanation:

A. to make the quadrilateral a parallelogram, we have:

7y + 5 = 8y - 4

112 = 10x - 8

<=> y = 5 + 4

120 = 10x

<=> x = 12

y = 9

B.we have:

17 = 4x + 5

63 = 8y - 1

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3 years ago

The cross-sectional areas of a right pyramid and a right cylinder are congruent. The right pyramid has a height of 10 units, and

Ilia_Sergeevich [38]

Answer:

The volume of the cylinder is 2.1 times the volume of the pyramid

Step-by-step explanation:

step 1

Find the volume of the pyramid

we know that

The volume of a right pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base of pyramid

H is the height of the pyramid

we have

$H=10\ units$

substitute

$Vp=\frac{10}{3}B\ units^{3}$

step 2

Find the volume of the right cylinder

we know that

The volume of right cylinder is equal to

$V=BH$

where

B is the area of the base of cylinder

H is the height of the cylinder

we have

$H=7\ units$

substitute

$Vc=7B\ units^{3}$

step 3

Compare the volumes

we know that

The area of the base both figures are congruent

Find the ratio of their volumes

$\frac{Vp}{Vc}$

substitute

$\frac{Vp}{Vc}=\frac{(\frac{10}{3}B)}{7B}$

Simplify

$\frac{Vp}{Vc}=\frac{10}{21}$

$21Vp=10Vc\\\\Vc=2.1Vp$

therefore

The volume of the cylinder is 2.1 times the volume of the pyramid

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