The width of a rectangle is three times its height. If it has an area of 60.75 square feet, what are its dimensions?

Mathematics

2 answers:

horrorfan [7]2 years ago

8 0

The answer is D my dude don’t over think. Since it’s are multiply your answer choices till you reach 60.75

LuckyWell [14K]2 years ago

3 0

Answer

d. 13.5 ft by 4.5 ft

Step-by-step explanation:

Let height of rectangle be x ft

Therefore, width = 3x ft

$area \: of \: rectangle = 60.75 \: {ft}^{2} \\ \therefore \: lw = 60.75 \\ \therefore \: 3x \times x = 60.75 \\ \therefore \: 3x^{2} = 60.75 \\ \therefore \: x^{2} = \frac{60.75}{3} \\ \therefore \: x^{2} = 20.25 \\ \therefore \:x = \sqrt{20.25} \\ \therefore \:x = 4.5 \: ft\\ \therefore \:3x =3 \times 4.5 = 13.5 \: ft$

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