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3 years ago

Find rhe volume of a cylinder with a diameter of 10 inches and a height of 20 inches

1 answer:

7 0

Since the diameter of the cylinder is 10, its radius is half that, or 5, thus

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=5\\
h=20
\end{cases}\implies V=\pi (5)^2(20)$

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lim with x yields infinity below left parenthesis fraction numerator t left parenthesis 2 over denominator 2 end fraction s to t

Aleksandr [31]

Answer:

The vertical asymptotes are x=3 and x=-3. The horizontal asymptote is y=20.

Step-by-step explanation:

The given function is

Equate the denominator equal to 0, to find the vertical asymptotes.

Add 9 on both sides.

Taking square root on both sides.

Therefore the vertical asymptotes are x=3 and x=-3.

The given function can be written as

Degree of numerator and denominator are same.If degree of numerator and denominator are same, then horizontal asymptote is

Therefore the horizontal asymptote is y=20.

Step-by-step explanation:

Hope this helps:)

3 0

3 years ago

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Andru [333]

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7 0

3 years ago

Write <img src="https://tex.z-dn.net/?f=%282a%29%5E3" id="TexFormula1" title="(2a)^3" alt="(2a)^3" align="absmiddle" class="late

Gre4nikov [31]

Hello ;
(2a)^3 =(2)^3 (a)^3 = 8(a)^3

7 0

4 years ago

Read 2 more answers

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

4 years ago

Help me<br> ..........,..........................

saw5 [17]

Hi there!
The answer you're looking for is
218 because 10+4 exponent 4 - 6 x 8 that's the parenthesis then you find the answer to the exponent = 10 + 256 - 48 Then you add and subtract 10+256-48=218 Hope it helps <3

3 0

3 years ago