Step-by-step explanation:
Well to set up a substitution equation, you need to make sure you have something you can sub in that's identical in both equations.
we have
3x-y=5
x-4y=-24
what's in common? x and y.
take one of the equations and solve for x or y like so (i'm doing y)
3x-5=y
then substitute the whole 3x-5 equation for y in the second equation. it is quite similar to how you would normally substitute a number like if y=5, then you substitute 5 for y in the second equation, but instead the "5" is an equation "3x-5"
x-4y=-24
x-4(3x-5) = -24
Now that you got it set up, you just need to solve for x and once you got x value, plug the x value in the original equations to find y.
The answer is likely to be 6
Answer:
C
Step-by-step explanation:
Q: 1/5 + 5/6 = 6/11?
Convert fractions to have a common denominator
6/30 + 25/30 = 31/30
31/30 = 6/11?
No
31/30 is closer to 1
Long answer:
The domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}
Hence the range is all real numbers except -3 and 3. Hence, range R: (–∞, –3) ∪ (3, ∞)
Given the following functions:
First we need to get the composite function f(g(x))
Get the domain
The domain the values of x for which the function exists. The function cannot exists at when x = -6 and x = 0
Hence the domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}
The range is the value of y for which the function exists. The function cannot exists at when x = -6 and x = 0
Hence the range is all real numbers except -3 and 3. Hence, range R: (–∞, –3) ∪ (3, ∞)