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Ira Lisetskai [31]

3 years ago

10

How do I factor out the coefficient of the variable 2b+8

1 answer:

inn [45]3 years ago

4 0

2 (b+4)
2 being the factored coefficient

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Solve the following by substitution : -<br><br>x + y = 10<br>x - y = 5

koban [17]

$\begin{cases} x + y = 10 \\ x - y = 5 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x - y = 5 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x - (10-x) = 5 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x - 10+x = 5 \end{cases}\\ \\$

$\begin{cases} y = 10 -x\\ 2x - 10 = 5 \end{cases}\\ \\\begin{cases} y = 10 -x\\ 2x = 5 +10 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ 2x =15 \ \ /:2 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x =\frac{15}{2} \end{cases}\\ \\$

$\begin{cases} y = 10 - 7\frac{1}{2}\\ x =7\frac{1}{2} \end{cases}\\ \\ \begin{cases} y = 2\frac{1}{2}\\ x = 8\frac{1}{2} \end{cases}\\ \\$

7 0

2 years ago

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Digiron [165]

What I gather from the question is that $X$ has second moment $E(X^2)=81$ and variance $V(X) = 58$ , and you're asked to find the expectation and variance of the random variable $Y=2X+10$ .

From the given second moment and variance, we find the expectation of $X$ :

$V(X) = E(X^2) - E(X)^2 \implies E(X) = \sqrt{E(X^2) - V(X)} = \sqrt{23}$

Expectation is linear, so

$E(Y) = E(2X+10) = 2 E(X) + 10 = \boxed{2\sqrt{23} + 10}$

Using the same variance identity, we have

$V(Y) = V(2X+10) = E((2X+10)^2) - E(2X+10)^2$

and

$E((2X+10)^2) = E(4X^2 + 40X + 100) = 4E(X^2) + 40E(X) + 100 = 424 + 40\sqrt{23}$

so that

$V(Y) = V(2X+10) = (424 + 40\sqrt{23}) - (2\sqrt{23} + 10)^2 = \boxed{232}$

Alternatively, we can use the identity

$V(aX+b) = a^2 V(X) \implies V(2X+10) = 4V(X) = 232$

5 0

1 year ago

I need helppppp........

grin007 [14]

Answer:

B

Step-by-step explanation:

To do this, you need to complete the square.

$y=-2x^2-8x-13 \\\\y=-2(x^2+4x)-13 \\\\y=-2(x^2+4x+4)+8-13 \\\\y=-2(x+2)^2-5$

Therefore, the correct answer is choice B. Hope this helps!

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3 years ago

Natalie saved $20 when she purchased a new phone. The phone originally cost $125. What percent savings did Natalie receive on th

Free_Kalibri [48]

15% I think, I’m pretty sure I’m right

6 0

2 years ago

Solve for h in this equation

Mariana [72]

$a = \frac{1}{2} (b1 + b2)h \\ \frac{a}{\frac{1}{2} (b1 + b2)} = h \\ \frac{2a}{b1 + b2} = h$

6 0

2 years ago

Read 2 more answers