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Maksim231197 [3]
3 years ago
11

Find the measure of angle x in the figure below: 60° 50° 110° 70°

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

Step-by-step explanation:

Consider A=60°, B=50°, C=y°=???

So, according to the measurement of angles of a triangle.

A+B+C= 180°

60°+80°+C= 180°

140°+C=180°

C=180°-140°

C=y°=40°

So, x is also 40° since x and y are vertically opposite angles.

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If 0 lies in the quadrant IV. What can be the value of cos 0?
Andru [333]

Answer:

Positive one

Step-by-step explanation:

The angle 0 does not lie in any of the four quadrants, it lands directly in between quadrants I and IV. The value of cos 0 is always 1.

4 0
3 years ago
The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.
puteri [66]

Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

  • l is length
  • w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]:                                                                              \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Area of Rectangle] Product Rule:                                                                 \displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}

<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
  2. [Rate] Multiply:                                                                                                \displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day
  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

8 0
3 years ago
Based on the graph what are the solutions to ax^2 + bx+c=0 Select all that apply
AlexFokin [52]

Answer:

x=-2 and x = 5

Step-by-step explanation:

The solutions to the equation are where the graph crosses the x axis

We can see that the graph crosses at x=-2 and x = 5

8 0
3 years ago
Read 2 more answers
4/5 equivalent fraction?
Grace [21]
4/5 = 8/10 = 12/15 = 16/20 = 20/25
Hope it  helps
6 0
3 years ago
The solution set for -p2 − 11p = 0 is { }. (Separate the solutions with a comma.)
ikadub [295]

Answer:

0,-11

Step-by-step explanation:

-p^2 − 11p = 0

Factor out -p

-p( p+11) =0

Using the zero product property

-p =0    p+11 =0

p =0      p = -11

3 0
3 years ago
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