The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
ses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions. She determines that x must be between 0 and 10 and y must be between 20 and 40. Determine if Chaneece found the correct solution. If not, state the correct solution. A) Yes, Chaneece found the correct solution.
B) No, Chaneece mixed up the variables. The correct solution is that x must be between 20 and 40 and y must be between 0 and 10.
C) No, Chaneece should not have restricted the solution to quadrant I. The correct solution is that x can be all real numbers and y must be less than 10.
D) No, Chaneece looked at the wrong area of the shaded graph. The correct solution is that x must be between 0 and 30 and y must be between 0 and 40.
<span>Chaneece chooses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions.
</span>y ≤ 40 – x, if x must be between 0 and 10, y must be between 20 and 40 <span>it is true proof </span><span>for x=0 and y=10, y ≤ 40 – x equivalent to 10<40-0=40 it is true </span>x=10, y=30, <span>y ≤ 40 – x equivalent to 30=40-10=30 it is true
the answer is </span><span>A) Yes, Chaneece found the correct solution. </span>
I've had a problem similar to this before. He should start out with 0 flowers. He would have 2 flowers at the first one, so he would put one on the first grave then have one for the second. When he gets to the second, he puts down one flower and the last flower on the 3rd grave.
