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Leno4ka [110]
3 years ago
7

Relative to the circle with the equation x^2 + y^2 = 4 how has the circle with the equation (x+5)^2 + (y-6)^2 = 4 been shifted,

what is the radius of the circle
Mathematics
2 answers:
jolli1 [7]3 years ago
5 0
Math is so not my thing its so hard
mixas84 [53]3 years ago
3 0

Answer:

the circle is shifted -5 on the x and +6 on the y. Center is (-5,6). Radius = 2.

Step-by-step explanation:

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Please help I’ll give brainliest
strojnjashka [21]

\implies {\blue {\boxed {\boxed {\purple {\sf {D. \:  {9}^{2} }}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

{9}^{5}  \div  {9}^{3}

➼\:  {9}^{5 - 3}

➼\:  {9}^{2}

<h3><u>Note</u>:-</h3>

{a}^{m}  \div  {a}^{n}  =  {a}^{m - n}

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

7 0
3 years ago
A deli sells sliced meat and cheese. One customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50. A san
eimsori [14]

Answer:

The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.

Step-by-step explanation:

Let the cost of 1 pound of meat be x

Let the cost of 1 pound of cheese be y

Cost of 4 pounds of meat = 4x

Cost of 5 pounds of cheese = 5y

Since we are given that one customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50.  

So, equation becomes :

Cost of 11 pounds of meat = 11x

Cost of 14 pounds of cheese = 14y

Since we are given that a sandwich shop owner comes in and purchases 11 pounds of meat and 14 pounds of cheese for $84.50.

So, equation becomes :

Thus the system of equations are :

-1   (Red line)

-2   (Black line)

Solving these equations graphically we get the solution

x = $4.5

y = $2.5

Hence The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.

5 0
2 years ago
Whats the answer of -5+-2p=-9
Nikolay [14]

Answer:

p = 2

Step-by-step explanation:

Step 1: Write equation

-5 + -2p = -9

Step 2: Solve for <em>p</em>

<u>Simplify:</u> -5 - 2p = -9

<u>Add 5 to both sides:</u> -2p = -4

<u>Divide both sides by -2:</u> p = 2

Step 3: Check

<em>Plug in p to verify it's a solution.</em>

-5 - 2(2) = -9

-5 - 4 = -9

-9 = -9

7 0
3 years ago
Read 2 more answers
The number of people arriving for treatment at an emergency room can be modeled by a Poisson Distribution with a rate parameter
AlekseyPX

Answer:

a) 0.052 = 5.2% probability that exactly three arrivals occur during a particular hour

b) 0.971 = 97.1% probability that at least three people arrive during a particular hour

c) 5.25 people are expected to arrive during a 45-min period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson Distribution with a rate parameter of seven per hour.

This means that \mu = 7

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.052

0.052 = 5.2% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour? (Round your answer to three decimal places.)

Either less than three people arrive, or at least three does. The sum of the probabilities of these events is 1. So

P(X < 3) + P(X \geq 3) = 1

We want P(X \geq 3), which is

P(X \geq 3) = 1 - P(X < 3)

In which

P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.001

P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.006

P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.022

So

P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.001 + 0.006 + 0.022 + 0.029

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.029 = 0.971

0.971 = 97.1% probability that at least three people arrive during a particular hour

(c) How many people do you expect to arrive during a 45-min period?

During an hour(60 minutes), 7 people are expected to arrive. So, using proportions:

\frac{45*7}{60} = \frac{3*7}{4} = \frac{21}{4} = 5.25

5.25 people are expected to arrive during a 45-min period

5 0
3 years ago
PLEASEEEE HELP!! This is my SECOND time asking :((
adoni [48]

Answer:

C

Step-by-step explanation:

formula: <u>Y</u><u>2</u><u> </u><u>-</u><u> </u><u>Y</u><u>1</u>

X2 - X1

-18 = X1

16 = Y1

31 = X2

40 = Y2

<u>4</u><u>0</u><u> </u><u>-</u><u> </u><u>1</u><u>6</u><u>. </u><u> </u><u> </u> = <u>2</u><u>4</u>

31 - (-18) 49

3 0
3 years ago
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