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grin007 [14]
4 years ago
15

I dont get this problem, could you explain it to me? P/3 plus (-7) = 5don't get this problem, could you explain it to me? P/3 ➕

(-7) =5
Mathematics
1 answer:
LekaFEV [45]4 years ago
7 0

Answer:

Step-by-step explanation:

Okay so first you have to get rid of the -7

P/3 ➕ (-7) = 5. Add 7 to both sides because that the opposite of subtracting

p/3= 5+7=12

now, multiply by 3 because that is the opposite of dividing

p=12*3= 36

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Find the given derivative by finding the first few derivatives and observing the pattern that occurs. d103 dx103 (sin(x))
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To find \frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right), we find the first few derivatives and observe the pattern that occurs.

\frac{d}{dx} (\sin{(x)})=\cos{(x)} \\  \\  \frac{d^2}{dx^2} (\sin{(x)})= \frac{d}{dx} (\cos{(x)})=-\sin{(x)} \\  \\ \frac{d^3}{dx^3} (\sin{(x)})= -\frac{d}{dx} (\sin{(x)})=-\cos{(x)} \\  \\ \frac{d^4}{dx^4} (\sin{(x)})= -\frac{d}{dx} (\cos{(x)})=-(-\sin{(x)})=\sin{(x)} \\  \\ \frac{d^5}{dx^5} (\sin{(x)})=  \frac{d}{dx} (\sin{(x)})=\cos{(x)}

As can be seen above, it can be seen that the continuos derivative of sin (x) is a sequence which repeats after every four terms.

Thus,

\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)= \frac{d^{4(25)+3}}{dx^{4(25)+3}} \left(\sin{(x)}\right) \\  \\ = \frac{d^3}{dx^3} \left(\sin{(x)}\right)=-\cos{(x)}

Therefore,

\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)=-\cos{(x)}.
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